<h3 /><h3>
![\frac{3}{4} + \frac{1}{5} = \frac{4}{9} \\ \frac{3 \times 5}{4 \times 5} + \frac{1 \times 4}{5 \times 4} = \frac{4}{9} \\ \frac{15 + 4}{20} = \frac{4}{9} \\ \frac{19}{20} ≠ \frac{4}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20%20%2B%20%20%5Cfrac%7B1%7D%7B5%7D%20%20%3D%20%20%5Cfrac%7B4%7D%7B9%7D%20%20%5C%5C%20%20%5Cfrac%7B3%20%5Ctimes%205%7D%7B4%20%5Ctimes%205%7D%20%20%2B%20%20%5Cfrac%7B1%20%5Ctimes%204%7D%7B5%20%5Ctimes%204%7D%20%20%3D%20%20%5Cfrac%7B4%7D%7B9%7D%20%20%5C%5C%20%20%5Cfrac%7B15%20%2B%204%7D%7B20%7D%20%20%3D%20%20%5Cfrac%7B4%7D%7B9%7D%20%20%5C%5C%20%20%5Cfrac%7B19%7D%7B20%7D%20%E2%89%A0%20%5Cfrac%7B4%7D%7B9%7D%20)
</h3>
THIS SHOWS THAT YOUR ANSWER IS NOT CORRECT.
<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>
The probability of picking 2 white balls and 1 black ball is 0.154
<h3>How to determine the probability?</h3>
The given parameters are:
- Number of balls, n = 20
- White = 12
- Black = 8
When each ball is selected, the total number of ball decreases by 1 and the type of ball also decreases.
So, the probability is represented as:
P(2 white and 1 black) = White/n * White - 1/n - 1 * Black//n - 2
Substitute known values
P(2 white and 1 black) = 12/20 * 11/19 * 8//18
Evaluate
P(2 white and 1 black) = 0.154
Hence, the probability of picking 2 white balls and 1 black ball is 0.154
Read more about probability at:
brainly.com/question/251701
#SPJ1
Answer: sentence 4
Step-by-step explanation:
Answer:
Step-by-step explanation:305,464
Answer:
$18.59
Step-by-step explanation:
19.16=100%
0.1916=1%
97(0.1916)
18.59