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Charra [1.4K]
2 years ago
11

Ill give brainliest if u answer right:) pls help

Mathematics
1 answer:
sesenic [268]2 years ago
8 0

Answer:

I think the answer is number 8

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9c - 10 = 2c + 53 <br>find what is c.​
NARA [144]

Answer:

c = 9

Step-by-step explanation:

9c - 10 = 2c + 53

9c =2c + 63

7c = 63

c = 9

5 0
3 years ago
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Someone please help me with this :(
ratelena [41]

Answer:

Please find attached pdf

Step-by-step explanation:

7 0
2 years ago
1 1/2 is what % of 7 1/2 and also 7 1/2 is what % of 1 1/2?
Nataly [62]
Answer
20% for the first one
3 0
3 years ago
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[02.03]
SVEN [57.7K]

Answer:

2)  Equation 1 and Equation 2 have the same number of solutions.

Step-by-step explanation:

The two given equations are

1)  15x + 6 = 41                and                   2) 2x + 13 = 28

Solving both equations, we get

Solving (1) :   15x + 6 = 41 ⇒   15x  = 41 -  6 = 35

or, x = 35/15 ⇒ x = 7/3

Solving (2) :   2x + 13 = 28⇒   2x  = 28 -  13  = 15

or, x = 15/2 ⇒ x = 15/2

So, from above solutions we can say that Equation 1 and Equation 2 have the same number of UNIQUE solution.

6 0
3 years ago
I need help with this
andre [41]

Answer:

  f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}

Step-by-step explanation:

Each vertical asymptote corresponds to a zero in the denominator. When the function does not change sign from one side of the asymptote to the other, the factor has even degree. The vertical asymptote at x=-4 corresponds to a denominator factor of (x+4). The one at x=2 corresponds to a denominator factor of (x-2)², because the function does not change sign there.

__

Each zero corresponds to a numerator factor that is zero at that point. Again, if the sign doesn't change either side of that zero, then the factor has even multiplicity. The zero at x=1 corresponds to a numerator factor of (x-1)².

__

Each "hole" in the function corresponds to numerator and denominator factors that are equal and both zero at that point. The hole at x=-3 corresponds to numerator and denominator factors of (x-3).

__

Taken altogether, these factors give us the function ...

  \boxed{f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}}

8 0
3 years ago
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