So, all percents can be expressed as *percent*/100
So for this, it would be 150/100
Then we want to simplify it down and all that jazz. Find the biggest number that BOTH the numerator AND denominator can be divided by.
In this case, 50.
150/50=3
100/50=2
So now you have 3/2
You might also want a mixed number, or, a whole number with the leftover fraction after it.
In this case, see how many times can 2 go into 3 FULLY.
The answer would be 1. 1 is our WHOLE NUMBER.
Then take whatever is left over from 3 and that is our numerator. Do this, since 2 can go into 3 ONE time FULLY, I can say 3-(2*1) is our remainder.
That gives you one as the numerator. 2 is still the denominator.
So a mixed number of 3/2 is 1 1/2
So here is 150% as a fraction: 150/100, 3/2 or 1 1/2.
I hope I helped!!! -Kibeye/Ethan
Answer:
= 
Step-by-step explanation:
Differentiate xy using the product rule, then
Given
x - y = xy
1 - = x. + y. 1 = x + y ( subtract 1 from both sides )
- = x + y - 1 ( subtract x from both sides )
- - x = y - 1 ( multiply through by - 1 )
+ x = 1 - y
(1 + x) = 1 - y ← divide both sides by (1 + x)
=
Answer:$430
Step-by-step explanation: 40*4 for the first amount of cloth, 6*45 for the second amount. Add those two together and you get 430
Answer:
decimal form would be 0.375
these are all also equivalent 6/16 9/24 12/32 15/40 18/48 21/56 24/64 27/72 30/80 33/88 36/96 .375
i would just pick the one you have the options with since you just asked a question with no choices but i hope this helps
Step-by-step explanation:
Answer:
c. No, there are more than two possible outcomes for each trial.
Step-by-step explanation:
Binomial probability distribution:
Only two possible outcomes, success or failure.
In each trial, the probability of a success must be the same.
The number of trials must be fixed.
You ask ten randomly chosen college students to rate their experience at the dining hall on a scale of 1-5.
There are 10 trials, which is a fixed number and respects the binomial distribution. However, there are five possible outcomes(numbered 1 to 5). Since there is more than two possible outcomes, the scenario cannot be modeled using a binomial distribution, and the correct answer is given by option c.
