The green square is 18 and the red is 32
Answer:
b. -x^2 + 50 = 25
c. |2x| = 10
d. x < 0
e. 2x < 10
Step-by-step explanation:
x = -5
-(-5)² + 50
-25 + 50 = 25
|2(-5)| = |-10| = 10
-5 < 0
2(-5) = -10 < 10
Answer:
pic one is rock cycle, pic 2 crystaline structure, and pic three and 4 are the same pictures as question 2
Step-by-step explanation:
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
Let g(x) = 2x and h(x) = x2 + 4. Evaluate (h ∘ g)(−2).
A. −12
the corrects answer is <em>B. −16
</em>
C. 20
D. 16
