What is the following product?<br> 35 2

Circle the following 2 terms that correspond with the domain of a function:

Nitella [24]

Answer:

x-values

independent variable

Step-by-step explanation:

x (the independent variable) is the domain

y (the dependent variable) is the range

8 0

3 years ago

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Refer to the technology output given to the right that results from measured hemoglobin levels (g/dL) in 100 randomly selected a

charle [14.2K]

Answer:

Step-by-step explanation:

a)

Confidence interval in less than symbol expressed as

$\bar{x} - E < \mu < \bar{x} + E
$

Where $\bar{x}$ is sample mean and $E$ is margin of error.

$13.03 < \mu 13.42
$

b)

The given t interval is $(13.032 , 13.418 )
$

That is $\bar{x} - E = 13.032$ and $\bar{x} + E = 13.418$

Solve these two equation by adding together.

$2 \bar{x} = 13.032 + 13.418
\\\\\bar{x} = 13.225$

Solve this value of \bar{x} in equation $\bar{x} - E = 13.032$ and solve for $E$

$13.225 - E = 13.032
\\\\E = 0.193
$

Best point estimate of $\mu = \bar{x} = 13.225
$

Best point estimate of margin of error = 0.193

c)

Since sample size = 100 which is sufficiently large (Greater than 30) , it is no need to confirm that

sample data appear to be form a population with normal distribution.

8 0

2 years ago

Keira goes shopping at a supermarket

Damm [24]

What is the rest of it

6 0

3 years ago

Suppose a simple random sample of size n is drawn from a large population with mean mu and standard deviation sigma. The samplin

Sidana [21]

Answer:

$X \sim N(\mu,\sigma)$

Where $\mu$ the mean and $\sigma$ the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = \mu$

$\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,\sigma)$

Where $\mu$ the mean and $\sigma$ the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = \mu$

$\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}$

6 0

2 years ago

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4 x plus 8 y equals 40, when y equals 0.8?