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Makovka662 [10]
2 years ago
6

What is (−8 3/4)÷2 1/6?

Mathematics
1 answer:
docker41 [41]2 years ago
5 0

Answer:

-4.03846153846

Step-by-step explanation:

done

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The function g(t) = - 16t2 + vt + h represents the height of an object, g, in feet, above the ground in relation to the time, t,
timurjin [86]

Answer:

g(t) = -16t^2+80t.

Step-by-step explanation:

We are given that v=80 and h=0 (because that's the ground), so substituting that into g(t) = -16t^2+vt+h gives g(t) = -16t^2+80t.

5 0
2 years ago
Read 2 more answers
during a softball game kay hit a fly ball the function f(x) = -16t^2 + 64t + 4 describes the height of the softball in feet. mak
STatiana [176]
<h2>Hello!</h2>

The graph is attached.

To graph a parabola we need to know the following:

- If the parabola is open upwards or downwards

- They axis intercepts (if they exist)

- The vertex position (point)

We are given the function:

f(t)=-16t^{2}+64t+4

Where,

a=-16\\b=64\\c=4

For this case, the coefficient of the quadratic term (a) is negative, it means that the parabola opens downwards.

Finding the axis interception points:

Making the function equal to 0, we can find the x-axis (t) intercepts, but since the equation is a function of the time, we will only consider the positive values, so:

f(t)=-16t^{2}+64t+4\\0=-16t^{2}+64t+4\\-16t^{2}+64t+4=0

Using the quadratic equation:

\frac{-b+-\sqrt{b^{2}-4ac } }{2a}=\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}\\\\\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}=\frac{-64+-\sqrt{4096+256} }{-32}\\\\\frac{-64+-\sqrt{4096+256} }{-32}=\frac{-64+-(65.96) }{-32}\\\\t1=\frac{-64+(65.96) }{-32}=-0.06\\\\t2=\frac{-64-(65.96) }{-32}=4.0615

So, at t=4.0615 the height of the softball will be 0.

Since we will work only with positive values of "x", since we are working with a function of time:

Let's start from "t" equals to 0 to "t" equals to 4.0615.

So, evaluating we have:

f(0)=-16(0)^{2}+64(0)+4=4\\\\f(1)=-16(1)^{2}+64(1)+4=52\\\\f(2)=-16(2)^{2}+64(2)+4=68\\\\f(3)=-16(3)^{2}+64(3)+4=52\\\\f(4.061)=-16(4.0615)^{2}+64(4.0615)+4=0.0034=0

Finally, we can conclude that:

- The softball reach its maximum height at t equals to 2. (68 feet)

- The softball hits the ground at t equals to 4.0615 (0 feet)

- At t equals to 0, the height of the softball is equal to 4 feet.

See the attached image for the graphic.

Have a nice day!

3 0
3 years ago
HELP! What is the volume in cubic inches of the solid figure, rounded to the nearest cubic inch?
Setler [38]

Answer:

Volume of the solid figure = 1131 cubic inches

Step-by-step explanation:

Volume of solid figure = Volume of half cylindrical prism + Volume of the rectangular prism

Volume of half cylindrical prism = \frac{1}{2}(\pi r^2h)

                                                     = (\frac{1}{2})(\pi )(17-11)^2(6)

                                                     = 339.29 cubic inch.

Volume of the rectangular prism = (length × width × height)

                                                      = 11 × 6 × 12

                                                      = 792 cubic inches

Volume of the solid figure = 339.29 + 792

                                            = 1131.29

                                            ≈ 1131 cubic inches

8 0
3 years ago
Find the equivalent fraction for 10/20
dezoksy [38]
\frac{10}{20} =  \frac{ \frac{10}{10} }{ \frac{20}{10} } =  \frac{1}{2}
6 0
3 years ago
Can anyone help me? I need an exact answer, please no guesses. Thanks in advance
tia_tia [17]
45 degrees
160 - 115
6 0
3 years ago
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