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3 years ago

Use your calculator to find an interval of length 0.01 that contains a root. (enter your answer using interval notation.)

1 answer:

6 0

<span>Given a function, if you suspect a root lies near a specific point on the number line, you can evaluate the function at several nearby values and see whether the evaluation is positive or negative. Using a calculator, you should find two real numbers that are at distance 0.01 from one another, such that one real number evaluates positive, and the other evaluates negative. Then the interval between these values contains a root.</span>

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If cos theta = 0.5, find sec theta. A. 0.25 B. 0.5 C. 1 D. 2

Vsevolod [243]

Sec theta = 1/cos theta = 1/0.5 = 2

Option D is the correct answer.

4 0

2 years ago

A shoe box in the shape of a rectangular prism has a length of 12 inches, a width of 6 1/2 inches, and a height of 4 1/2 inches.

katovenus [111]

12 x 6 1/2 x 4 1/2 = 351in^3

3 0

3 years ago

Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ < 55 A sample of 36 is used. Identify the p-value and state your con

Ket [755]

Answer:

Step-by-step explanation:

Given that:

$H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55$

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }$

$Z = \dfrac{-1}{\dfrac{5.3}{6} }$

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

For x = 53 and s = 4.6

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }$

$Z = \dfrac{-2}{\dfrac{4.6}{6} }$

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

$Conclusion: \ There \ is \ sufficient \ evidence \ to \ conclude \ that$ $\mu < 55$

For x = 56 and s = 5.0

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }$

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

6 0

3 years ago

Fiona and her friends are playing a game by guessing where a coin will land when it is randomly dropped inside the square shown

Butoxors [25]

i'm 85% certain the answer is C. Fiona is not correct because the coin will definitely land in the white area .

8 0

2 years ago

Oil prices are projected to increase by 50% by next March. A quart of oil currently costs $1.85. What is the projected cost of a

Zolol [24]

Answer:

$11.10 per gallon.

Step-by-step explanation:

There are 4 quarts in a gallon so the cost of a gallon of oil currently is 1.85×4=$7.40

If the gallon price of oil goes up 50% then our answer is: 7.40× $\frac{3}{2}$ = $\frac{22.2}{2}$ =11.1

The price of oil in March will be $11.10 per gallon.

6 0

2 years ago