3 years ago

Use your calculator to find an interval of length 0.01 that contains a root. (enter your answer using interval notation.)

1 answer:

6 0

<span>Given a function, if you suspect a root lies near a specific point on the number line, you can evaluate the function at several nearby values and see whether the evaluation is positive or negative. Using a calculator, you should find two real numbers that are at distance 0.01 from one another, such that one real number evaluates positive, and the other evaluates negative. Then the interval between these values contains a root.</span>

You might be interested in

Evaluate each expression if a= 12, b =9, c= -4 (a2/4b)+c

Contact [7]

Here it issssss #studywell

4 0

3 years ago

5ab-2 with positive exponents

saw5 [17]

Step-by-step explanation:

When the base is even it is positive when the base is odd it is negative

7 0

3 years ago

Help me lollllllllll!!!!!

Rom4ik [11]

Answer: (3, -4)

Step-by-step explanation:

x = 3

y = -4

7 0

3 years ago

See question in attached photo.

mars1129 [50]

I cannot see the photo

8 0

2 years ago

Read 2 more answers

[2/SEC(¶/3)•[lim x→0 x^3+8x+10]^2]/[lim θ→0 sinθ/θ]

Oliga [24]

Assuming the pilcrow is supposed to represent pi:

$\frac{\frac{2}{sec(\frac{\pi}{3})}*(\lim_{x \to 0} x^3+8x+10)^2}{ \lim_{\theta \to 0} \frac{sine(\theta)}{\theta}}\\\frac{\frac{2}{\frac{1}{cosine(\frac{\pi}{3})}}*((0)^3+8(0)+10)^2}{\frac{sine((0))}{(0)}}\\\frac{\frac{2}{\frac{1}{\frac{1}{2}}}*(0+0+10)^2}{\frac{0}{0}}\\\frac{\frac{2}{2}*(10)^2}{ \lim_{\theta \to 0} \frac{cosine(\theta)}{1}}\\\frac{100}{cosine((0))}\\\frac{100}{1}\\100$

100

4 0

3 years ago