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3 years ago

Fully factorise X^3 - 100

Mathematics

1 answer:

PIT_PIT [208]3 years ago

5 0

Answer:

(x-10)(x²+10x+100)

Step-by-step explanation:

Given the expression

X^3 - 100

This ca also be expressed as;

X^3 - 100 = X³ - 10³

a³-b³ = (a-b)(a²+b²+ab)

Substitute a = x and b = 10

X³ - 10³ = (x-10)(x²+10²+10x)

X³ - 10³ = (x-10)(x²+10x+100)

Hence the factored form is (x-10)(x²+10x+100)

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Wewaii [24]

Answer:

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Step-by-step explanation:

Subtract:

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3 years ago

Plz help brain fam!

Liono4ka [1.6K]

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Let's follow the procedure of keeping, switching, and flipping. You keep the first improper fraction, switch the division sign to a multiplication sign, and flip the second fraction. That would make it : $\frac{-9}{4}$ × $\frac{-2}{3}$ .

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3 years ago

Read 2 more answers

The product of two consecutive even numbers is 12 more than the square of the smaller number.

vivado [14]

Answer:

6 and 8

Step-by-step explanation:

Let's start off by thinking at what the question is asking us.

The product (multiplication) of two even numbers (x)(x+2) is which means =,

12 more (12) than the square of the smaller number (x).

So put that all together and you get (x)(x+2)=12+x^2=

Distribute the x, (x)(x+2)=

x^2+2x=x^2+12 Subtract x^2 from both sides.

2x=12

Divide both sides by 2 and you get x=6

So the two numbers are 6,8

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