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igomit [66]
3 years ago
15

4,864 divsion 2 it multiple 2 word probems

Mathematics
1 answer:
trasher [3.6K]3 years ago
3 0
<h3>4864÷2</h3><h3>2432×2</h3><h3>= 4864</h3>

please mark this answer as brainlist

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Maria can paddle her canoe 2 miles upstream against the current in the same time it would take her to paddle 6 miles downstream.
BigorU [14]
The answer is 2. Imagine Maria can paddle 4 miles in either direction if there was no current in 2 hours. But if we add the current then we would subtract 2 when she goes upstream so she would get 4-2 which is 2 miles. And would get an extra 2 miles going downstream. So 4+2= 6 miles.

So the speed of the current is 2 mph.

Hope this helps!
8 0
4 years ago
Solve the system using elimination tech
choli [55]

Answer:

Step-by-step explanation:

8x - 2y = 6

-8x + 4y = 12

2y = 18

y = 9

8x - 18 = 6

8x = 24

x = 3

(9, 3)

7 0
3 years ago
Solve 42x = 7{x-1)<br> How do I solve this problem
Nimfa-mama [501]

Answer:

-1/5

Step-by-step explanation:

42x=7[x-1]

42x=7x-7

42x-7x=-7

35x=-7

x=-1/5

3 0
3 years ago
The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price
inn [45]

Answer:

Product A has a greater percentage change in price.

Step-by-step explanation:

Part A:

The price f product A, f (<em>x</em>) after <em>x</em> years is given by: 

 f(x) = 0.69\cdot(1.03)^{x}

After <em>x</em> = 0 years, the price of product A is:

f(0) = 0.69\cdot(1.03)^{0}=0.69

After <em>x</em> = 1 years, the price of product A is:

f(1) = 0.69\cdot(1.03)^{1}=0.69\cdot (1+0.03)=0.69\cdot (1+3\%)

After 1 year, the price of product A is 3% times more than the original price.

This means that after one year, the new price is 103% of the original price, which means the price product A is increasing by 3%.

Again after <em>x</em> = 2 years, the price of product A is:

f(2) = 0.69\cdot(1.03)^{2}=[0.69\cdot (1+3\%)]\times (1.03)

This implies that after 2 years, the price of product A is 103% of the price after year 1.

This implies that the price of product A is 3% more than the previous year.

Thus, the price of product A is increasing each year by 3%.

Part B:

The data for Product B is as follows:

Time (t)          Price [f (t)]

   1                   10,100

   2                   10,201

   3                 10,303.01

   4                 10,406.04

Product B is clearly increasing in price.

Consider the changes in price of Product B in the following intervals of years:

  • Year 1 - Year 2:

Price in year 1 = $10,100

Price in Year 2 = $10,201

Compute the increase percentage as follows:

\text{Increase}\%=\frac{10201-10100}{10100}=0.01=1\%

  • Year 2 - Year 3:

Price in Year 2 = $10,201

Price in year 3 = $10,303.01

Compute the increase percentage as follows:

\text{Increase}\%=\frac{10303.01-10201}{10201}=0.01=1\%

  • Year 3 - Year 4

Price in year 3 = $10,303.01

Price in Year 4 = $10,406.04

Compute the increase percentage as follows:

\text{Increase}\%=\frac{10,406.04-10303.01}{10303.01}=0.09999\approx 0.01=1\%

It is quite clear that the price of product B increases by 1% each year.

Thus, Product A has a greater percentage change in price.

3 0
3 years ago
HELP!! RLLY EASY HELP I WILL MAKE 5 STARS AND BRAINLY IF CORRECT!
torisob [31]

Answer:

area of the parallelogram =base × height

area of the parallelogram = 7.5×2.8=21

area of parallelogram = 21 inches.

4 0
3 years ago
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