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3 years ago

Help fgyugyruyvuryfryvseycfyrbseutgbvheryyyaduiik

Mathematics

1 answer:

Kisachek [45]3 years ago

3 0

Answer:you have to divide

Step-by-step explanation:

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3 years ago

A poll asked 1057 American adults if they believe there was a conspiracy in the assassination of President Kennedy, and found th

AVprozaik [17]

Answer:

The 95% confidence interval of the proportion of Americans who believe in the conspiracy is $0.551< p < 0.610$

Step-by-step explanation:

From the question we are told that

The sample size is n =1057

The number that believe there was a conspiracy is k = 614

Generally the sample proportion is mathematically represented as

$\^ p = \frac{614}{1057 }$

=> $\^ p = 0.5809$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.96 * \sqrt{\frac{0.5809 (1- 0.5809)}{1057} }$

=> $E = 0.02975$

Generally 95% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.5809 - 0.02975< p < 0.5809 + 0.02975$

=> $0.551< p < 0.610$

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2 years ago