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LUCKY_DIMON [66]
3 years ago
6

A sample of gold has a mass of 96.5 g and a volume of 5.00 cm3. What is the density of gold in g/cm3

Chemistry
1 answer:
viva [34]3 years ago
4 0

Answer: The density would be p = 19.3 g/cm3 because

Explanation:  because if you calculate density the formula would be d = <u>m</u>

                                                                                                                             v

so just use the values giving and you get the answer  by plugging the 96.5 mass then 5 for the volume then divide it.

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Describe the porosity and permeability of Antarctic soil.
maksim [4K]

Antarctic soils exist, in general, they comprise a surface pavement (i.e., a layer of gravel, stones or boulders formed largely by weathering and the removal of fine materials mainly by wind action) and a seasonally thawed active layer over permafrost.

5 0
3 years ago
How many grams hydrogen in 4.5 mol H2SO4
swat32
H2SO4 ---> 2H^+ + SO4^2-

Hence n H+ = 9 mols

Mass of H = nM = (9*1) = 9g


Alternately

mass of H2SO4= nM= 4.5*98= 441

Mass of H= mass h2so4 * molar mass of H/molar mass of h2so4
Mass of H= 441 * 2/98 = 9g

4 0
3 years ago
What is 4/5-1/2-1/5​
zimovet [89]

Answer:

\frac{1}{10}

Explanation:

First write all numerators above the common denominator

4/5 - 1/2 - 1/2=

\frac{4-1}{5}- 1/2

Subtract the numbers

\frac{4-1}{5}- 1/2 =

\frac{3}{5} - \frac{1}{2}

Write all numerators above the least common denominator 10

\frac{3}{5} - \frac{1}{2} =

\frac{6-5}{10}

Subtract the numbers and you got your answer :)

8 0
3 years ago
Read 2 more answers
I’m confused on this
ExtremeBDS [4]

Answer:

B

Explanation:

The scientist had a wrong hypothesis?

7 0
4 years ago
Read 2 more answers
Producer gas is a fuel formed by passing air over red-hot coke (amorphous carbon). What mass of a producer gas that consists of
Karolina [17]

Producer gas is a fuel that is produced by burning biomass with an air deficit passed over red-hot coke (amorphous carbon). This gas is nothing but a mixture of gases such as hydrogen (H), carbon monoxide (CO), carbon dioxide (CO₂) and nitrogen (N₂).

The equation of producer gas is as follows -

                            CO₂ + 2N₂ (air) → CO + 2N₂

                            ΔH = -27.06 kcal

We know that,

1 Ton = 1000 kg

Mass of coke needed to form producer gas = 1.75 tons = 1750 kg

Given values,

Carbon monoxide (CO) = 25%  

Carbon dioxide (CO₂) = 5%

Nitrogen (N₂) = 70%

One mole of carbon dioxide reacts with two moles of nitrogen to form one mole of carbon monoxide and nitrogen (producer gas).

We know that, 1 ton (1000 kg) of coke produces 470 Nm³ of producer gas, i.e.

470 × 4.359 = 2048.73 kg

1000 kg of coke produces = 2048.73 kg of producer gas

∴ 1 kg of coke produces = 2048.73 ÷ 1000 kg of producer gas

∴ 1750 kg of coke produces = 2048.73 × 1750 / 1000 = 3585.28 kg of producer gas.

Percentage yield = 87%

                             = 3585.28 × 87/100

                             = 3119.19 kg of producer gas

                             = 3.44 tons

Learn more about coke here-

brainly.com/question/13105289

#SPJ4

7 0
2 years ago
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