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tiny-mole [99]
2 years ago
6

Producer gas is a fuel formed by passing air over red-hot coke (amorphous carbon). What mass of a producer gas that consists of

25% CO, 5.0% CO₂, and 70.% N₂ by mass can be formed from 1.75 metric tons of coke, assuming an 87% yield?
Chemistry
1 answer:
Karolina [17]2 years ago
7 0

Producer gas is a fuel that is produced by burning biomass with an air deficit passed over red-hot coke (amorphous carbon). This gas is nothing but a mixture of gases such as hydrogen (H), carbon monoxide (CO), carbon dioxide (CO₂) and nitrogen (N₂).

The equation of producer gas is as follows -

                            CO₂ + 2N₂ (air) → CO + 2N₂

                            ΔH = -27.06 kcal

We know that,

1 Ton = 1000 kg

Mass of coke needed to form producer gas = 1.75 tons = 1750 kg

Given values,

Carbon monoxide (CO) = 25%  

Carbon dioxide (CO₂) = 5%

Nitrogen (N₂) = 70%

One mole of carbon dioxide reacts with two moles of nitrogen to form one mole of carbon monoxide and nitrogen (producer gas).

We know that, 1 ton (1000 kg) of coke produces 470 Nm³ of producer gas, i.e.

470 × 4.359 = 2048.73 kg

1000 kg of coke produces = 2048.73 kg of producer gas

∴ 1 kg of coke produces = 2048.73 ÷ 1000 kg of producer gas

∴ 1750 kg of coke produces = 2048.73 × 1750 / 1000 = 3585.28 kg of producer gas.

Percentage yield = 87%

                             = 3585.28 × 87/100

                             = 3119.19 kg of producer gas

                             = 3.44 tons

Learn more about coke here-

brainly.com/question/13105289

#SPJ4

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Explanation: Hope this helps

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Which of the following numerical expressions gives the number of particles in 2.0 g of Ne?
mojhsa [17]

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