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elixir [45]
4 years ago
14

How many atoms are in 17.0 moles of Pb?

Chemistry
1 answer:
Oksanka [162]4 years ago
8 0
No. of atoms=mols*avagadros no.
N=n*No
N=17 * 6.022 *10^23
No. Of atoms=(17) (6.022*10^23)
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Please Help Me!
S_A_V [24]

Answer:

The answer to your question is      SO₂   +   3H₂    ⇒     H₂S   + 2H₂O

Explanation:

Reaction

                                SO₂   +   H₂    ⇒     H₂S   +  H₂O

                      Reactants           Elements            Products

                              1                   Sulfur                    1

                               2                  Hydrogen               4

                              2                   Oxygen                   1

This reaction is unbalanced so we need to balance it.

                              SO₂   +   3H₂    ⇒     H₂S   + 2H₂O

                      Reactants           Elements            Products

                              1                   Sulfur                   1

                              6                  Hydrogen               6

                              2                   Oxygen                  2

Now, the reaction is balanced

3 0
3 years ago
How are nymphs different from adult insects?
umka2103 [35]

Answer:

Explanation:

the nymph looks like a smaller version of the adult insect, & it also has no wings & molts.

4 0
3 years ago
Read 2 more answers
The reaction is proceeding at a rate of 0.0080 Ms-1 in 50.0 mL of solution in a system with unknown concentrations of A and B. W
Leokris [45]

Answer:

0.0010 mol·L⁻¹s⁻¹  

Explanation:

Assume the rate law is  

rate = k[A][B]²

If you are comparing two rates,

\dfrac{\text{rate}_{2}}{\text{rate}_{1}} = \dfrac{k_{2}\text{[A]}_2[\text{B]}_{2}^{2}}{k_{1}\text{[A]}_1[\text{B]}_{1}^{2}}= \left (\dfrac{\text{[A]}_{2}}{\text{[A]}_{1}}\right ) \left (\dfrac{\text{[B]}_{2}}{\text{[B]}_{1}}\right )^{2}

You are cutting each concentration in half, so

\dfrac{\text{[A]}_{2}}{\text{[A]}_{1}} = \dfrac{1}{2}\text{ and }\dfrac{\text{[B]}_{2}}{\text{[B]}_{1}}= \dfrac{1}{2}

Then,

\dfrac{\text{rate}_{2}}{\text{rate}_{1}} = \left (\dfrac{1}{2}\right ) \left (\dfrac{1}{2}\right )^{2} = \dfrac{1}{2}\times\dfrac{1}{4} = \dfrac{1}{8}\\\\\text{rate}_{2} = \dfrac{1}{8}\times \text{rate}_{1}= \dfrac{1}{8}\times \text{0.0080 mol$\cdot$L$^{-1}$s$^{-1}$} = \textbf{0.0010 mol$\cdot$L$^{-1}$s$^{-1}$}\\\\\text{The new rate is $\large \boxed{\textbf{0.0010 mol$\cdot$L$^\mathbf{{-1}}$s$^{\mathbf{-1}}$}}$}

8 0
3 years ago
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Aleks04 [339]
It's the rows. They are periods. (1,2,3,4,5,6,7 - the ones without the letters).
6 0
3 years ago
What is neutron number for calcium ​
notka56 [123]

Answer:

20 neutrons

Explanation:

(not really any just look at a periodic table)

5 0
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