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3 years ago

Can someone please help me with this?

Mathematics

1 answer:

lidiya [134]3 years ago

6 0

Answer:

11 degrees

Step-by-step explanation:

The bottom triangle has 2 given angle, therefore we know the 3rd angle has to be 29 degrees. Given that the 2 lines are parallel, we know that the upper triangle has 140, 29, and x degrees. 180-140-29=x=11 degrees

Hope this helped, feel free to leave a comment if you still have any questions!

Cheers!

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The ratio of the length of a rectangular field to its width is 4:3. If the length of the field is 100 meters, what is the perime

irina [24]

Answer:

350

Step-by-step explanation:

divide 100/4= 25

25*3=75 so width = 75 meters

perimeter= 2(l+w)

perimeter= 2(100+75)

perimeter= 2(175)

perimeter= 350

6 0

3 years ago

Please help.... me on this question

Sonja [21]

Answer:

a = 30 degrees; b = 60 degrees; and c = 105 degrees.

Step-by-step explanation:

Angle a and the 30 degree angle are vertical angles and thus are equal.

Since the interior angles of a triangle always add up to 180 degrees, 30 + b + 90 degrees = 180 degrees, so that b must be 60 degrees.

Angle c and the 75 degree angle are straight angles, and so their sum must be 180 degrees. Thus, c = 105 degrees.

8 0

3 years ago

An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each oth

sattari [20]

They are traveling at right angles to each other so we can say one is traveling north to south and the other west to east. Then we can say that there positions, y and x are:

y=150-600t x=200-800t

By using the Pythagorean Theorem we can find the distance between these two planes as a function of time:

d^2=y^2+x^2, using y and x from above

d^2=(150-600t)^2+(200-800t)^2

d^2=22500-180000t+360000t^2+40000-320000t+640000t^2

d^2=1000000t^2-500000t+62500

d=√(1000000t^2-500000t+6250)

So the rate of change is the derivative of d

dd/dt=(1/2)(2000000t-500000)/√(1000000t^2-500000t+6250)

dd/dt=(1000000t-250000)/√(1000000t^2-500000t+6250)

So the rate depends upon t and is not a constant, so for the instantaneous rate you would plug in a specific value of t...

...

To find how much time the controller has to change the airplanes flight path, we only need to solve for when d=0, or even d^2=0...

1000000t^2-500000t+62500=0

6250(16t^2-8t+1)=0

6250(16^2-4t-4t+1)=0

6250(4t(4t-1)-1(4t-1))=0

6250(4t-1)(4t-1)=0

6250(4t-1)^2=0

4t-1=0

4t=1

t=1/4 hr

Well technically, the controller has t<1/4 because at t=1/4 impact will occur :)

7 0

3 years ago

7x+4y-6z=-73<br> 8x+5y+6z=-59<br> -4x-8y-3z=46<br> y=

Oksanka [162]

Is this all one equation??

5 0

3 years ago

For a data set of the pulse rates for a sample of adult? females, the lowest pulse rate is 39 beats per? minute, the mean of the

Zarrin [17]

Answer:

a) The difference is of 35 beats per minute.

b) So 3.07 standard deviations below the mean.

c) Z = -3.07.

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean $\mu = 74$ , standard deviation $\sigma = 11.4$

a. What is the difference between the pulse rate of 39 beats per minute and the mean pulse rate of the? females?

39 - 74 = -35

The difference is of 35 beats per minute.

b. How many standard deviations is that? [the difference found in part? (a)?

|Z| when X = 39. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{39 - 74}{11.4}$

$Z = -3.07$

|Z| = 3.07

So 3.07 standard deviations below the mean.

c. Convert the pulse rate of 39 beats per minutes to a z score.

From item b. above, Z = -3.07.

5 0

2 years ago

Can someone please help me with this? ​

Can someone please help me with this?