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3 years ago

BRO I NEED HELP!!!!

1 answer:

7 0

Let A represent the speed of car A. Using your formula,
.. A*2 = D
.. (A +15)*1.5 = D . . . . . the same distance in a shorter time at a higher speed

Equating the two expressions for D, we get
.. 2A = 1.5(A +15)
.. 2A = 1.5A +22.5 . . . . . eliminate parentheses
.. 0.5A = 22.5 . . . . . . . . .subtract 1.5A
.. A = 22.5/0.5 = 45 . . . .divide by 0.5
Car B was 15 mph faster than this.

Car B traveled at 60 miles per hour.

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Find the centroid for an area defined by the equations y = x² + 3 and y = - (x – 2)² + 7

sergeinik [125]

First we need to find where the 2 graphs intercept.

x^2 + 3 = - (x^2 - 4x + 4) + 7
x^2 + 3 = -x^2 + 4x + 3
2x^2 - 4x = 0
2x(x - 2)

x = 0 , 2. are x coordinates of the 2 intercepts.

6 0

3 years ago

Plssss help<br><br>use the property that it says to solve the proportion ty

Kay [80]

Answer:

the answer is 45 over 6

Step-by-step explanation:

A shortcut is "2 x _____ is 6", which is 3.

Multiply 15 by 3 also, to get 45,

45/6

7 0

2 years ago

A man who is 6 feet tall casts a shadow that is 11 feet long. At the same time, a tree casts a shadow that is 33 feet long. What

Rina8888 [55]

Set up a proportion:

6 feet over 11 feet long equals x feet over 33 feet long

6/11 = x/33

198 = 11x

x = 18

The height of the tree is 18 feet tall

8 0

3 years ago

Read 2 more answers

A jewelry store has 311.75 ounces of 14-carat gold in stock.

WARRIOR [948]

Answer:

$\boxed{\text{(a) 86 necklaces; (b) \$2220}}$

Step-by-step explanation:

(a) Number of necklaces

3⁵/₈ = 3.625

$\text{No. of necklaces} = 311.75\text{ oz} \times \dfrac{\text{1 necklace}}{3.625\text{ oz}} = \textbf{ 86 necklaces}\\\\\text{You can make } \boxed{\textbf{86 necklaces}} \text{ from 311.75 oz of 14K gold}$

(b) Value of gold in each necklace

There are 3.625 oz of 14K gold in each necklace. Pure gold is 24K.

$\text{Mass of pure gold} = \text{3.625 oz} \times \dfrac{\text{14K}}{\text{24K}} = \text{2.1146 oz}$

Pure 24K gold is worth $1050/oz.

$\text{Value of pure gold} = \text{2.1146 oz} \times \dfrac{\text{\$1050}}{\text{1 oz}} = \textbf{\$2220}\\\\\text{The value of the gold in each necklace is } \boxed{\textbf{\$2220}}$

4 0

3 years ago

Solve using substitution <br> y= x+4<br> x-y= -4

never [62]

X-(x+4)=-4

X-x-4=-4
-4=-4

All real numbers

6 0

3 years ago