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777dan777 [17]
4 years ago
13

A bottle of soft drink is two thirds full. Jack drinks one quarter of the remaining soft drink. How full is the bottle now

Mathematics
2 answers:
marusya05 [52]4 years ago
8 0

We know that the bottle of soft drink has a remaining volume which is 2 / 3 of the original.

Since Jack drank 1 / 4 of the remaining volume, hence only 3 / 4 now finally remains, the total is:

 

(2 / 3) * (3 / 4) = 6 / 12 = 1 / 2

 

<span>Hence the bottle is now one half full</span>

Lostsunrise [7]4 years ago
8 0

Charli,

First find what 1/4 of 2/3 is.

1/4 of 2/3 = 1/6

(That is 1/4 times 2/3 = 1/6)

So, the bottle was 2/3 full, it is now ...

2/3 - 1/6

=4/6 - 1/6

= 3/6 or 1/2 full.

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Trava [24]
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8 0
3 years ago
Urgent help please :)
avanturin [10]

Answer:

7w

Step-by-step explanation:

2w^2-4w+9

w^2-w+2-4+9

w+7

7w

8 0
4 years ago
Fill in the blank 43_ _ _54
Oksana_A [137]

Answer:

The answer is add 4.

Step-by-step explanation:

I know this because if you add 4 to 43 that's 47 so that's 1 of the blanks. Add another 4 that's 51. that's another 1. and that's last one is add 4 which makes 54.

Hope this helps.

6 0
3 years ago
I need help ASAP :/ I need the explanation
PtichkaEL [24]

Is 17x-2 supposed to be angle T?   This is a bad question; demand better from your teachers.

Let's assume 17x-2 = angle T.    S is a right angle because it's subtended by a diameter, Thales' Theorem.  R is half 116 degrees, so 58 degrees.  T  is complementary, T=90-58=32 degrees.

17x -2 = 32

17x = 34

x = 2

Answer: 2

6 0
4 years ago
| 7 + m | - 4 &gt; 8
cestrela7 [59]

Answer:

m > 5 or m < -19

Step-by-step explanation:

We are given the Inequality:

\displaystyle \large{ |7 + m|  - 4 > 8}

First, add both sides by 4.

\displaystyle \large{ |7 + m|  - 4 + 4 > 8 + 4} \\  \displaystyle \large{ |7 + m|  > 12}

<u>A</u><u>b</u><u>s</u><u>o</u><u>l</u><u>u</u><u>t</u><u>e</u><u> </u><u>V</u><u>a</u><u>l</u><u>u</u><u>e</u><u> </u><u>P</u><u>r</u><u>o</u><u>p</u><u>e</u><u>r</u><u>t</u><u>y</u>

\displaystyle \large{ |a|  =  \sqrt{ {a}^{2} } }

Given a = any expressions and b = any positive numbers, zero or any expressions.

\displaystyle \large{ |a|  =  b \longrightarrow a =  \pm b}

From the Inequality, change > to equal

\displaystyle \large{ 7 + m   =   \pm12}

Subtract 7 both sides.

\displaystyle \large{  7 - 7 + m   =  \pm12 - 7} \\ \displaystyle \large{  m   =   \pm12 - 7}

±12-7 can be 12-7 = 5 or -12-7 = -19

\displaystyle \large{  m   =   5, - 19}

Refer to the attachment. The region is when the absolute value function is greater than constant function y = 12 or a blue horizontal line.

Since the absolute graph is above constant graph when x > 5 and x <-19.

Therefore,

\displaystyle \large{  m    >  5, m < - 19}

3 0
3 years ago
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