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2 years ago

8

1960 there were 3,000 million people on earth, in 1999 there were 6,000 million people on earth, what was the approximate rate o

f incresse in million of people

1 answer:

Alekssandra [29.7K]2 years ago

3 0

Answer:

76.9 million people each year.

Step-by-step explanation:

There was a 39 year difference between 1960 and 1999 so it would be 3000/39= 76.9....

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Answer:

$\displaystyle f'(4) = 63$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

Distributive Property

<u>Algebra I</u>

Expand by FOIL (First Outside Inside Last)
Factoring
Function Notation
Terms/Coefficients

<u>Calculus</u>

Derivatives

The definition of a derivative is the slope of the tangent line.

Limit Definition of a Derivative: $\displaystyle f'(x)= \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 7x² + 7x + 3

Slope of tangent line at x = 4

<u>Step 2: Differentiate</u>

Substitute in function [Limit Definition of a Derivative]: $\displaystyle f'(x)= \lim_{h \to 0} \frac{[7(x + h)^2 + 7(x + h) + 3]-(7x^2 + 7x + 3)}{h}$
[Limit - Fraction] Expand [FOIL]: $\displaystyle f'(x)= \lim_{h \to 0} \frac{[7(x^2 + 2xh + h^2) + 7(x + h) + 3]-(7x^2 + 7x + 3)}{h}$
[Limit - Fraction] Distribute: $\displaystyle f'(x)= \lim_{h \to 0} \frac{[7x^2 + 14xh + 7h^2 + 7x + 7h + 3] - 7x^2 - 7x - 3}{h}$
[Limit - Fraction] Combine like terms (x²): $\displaystyle f'(x)= \lim_{h \to 0} \frac{14xh + 7h^2 + 7x + 7h + 3 - 7x - 3}{h}$
[Limit - Fraction] Combine like terms (x): $\displaystyle f'(x)= \lim_{h \to 0} \frac{14xh + 7h^2 + 7h + 3 - 3}{h}$
[Limit - Fraction] Combine like terms: $\displaystyle f'(x)= \lim_{h \to 0} \frac{14xh + 7h^2 + 7h}{h}$
[Limit - Fraction] Factor: $\displaystyle f'(x)= \lim_{h \to 0} \frac{h(14x + 7h + 7)}{h}$
[Limit - Fraction] Simplify: $\displaystyle f'(x)= \lim_{h \to 0} 14x + 7h + 7$
[Limit] Evaluate: $\displaystyle f'(x) = 14x + 7$

<u>Step 3: Find Slope</u>

Substitute in <em>x</em>: $\displaystyle f'(4) = 14(4) + 7$
Multiply: $\displaystyle f'(4) = 56 + 7$
Add: $\displaystyle f'(4) = 63$

This means that the slope of the tangent line at x = 4 is equal to 63.

Hope this helps!

Topic: Calculus AB/1

Unit: Chapter 2 - Definition of a Derivative

(College Calculus 10e)

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