Answer:
(3y + 2)(3y² + 4y - 2) = 9y³ + 18y² + 2y - 4.
Step-by-step explanation:
(3y + 2)(3y² + 4y - 2)
Break it up into two seperate equations.
(3y(3y² + 4y - 2)) + ((2)(3y² + 4y - 2))
Distribute the 3y into the equation.
(9y³ + 12y² - 6y) + ((2)(3y² + 4y - 2))
Distribute the 2 into the equation.
(9y³ + 12y² - 6y) + (6y² + 8y - 4)
Combine like terms.
9y³ + 12y² + 6y² - 6y + 8y - 4
9y³ + 18y² + 2y - 4.