Answer:
The rock hits the ground between <u>2</u> seconds and <u>2.5</u> seconds after it is dropped
Step-by-step explanation:
The given table is presented as follows;
Therefore, the rock hits the ground between t = 2 seconds and t = 2.5 seconds after it is dropped.
Answer:
-I haven't done this, but I have copied and pasted from another question and answer from the user syed514:
Graphing is one way to do the problem.But sometimes, graphing it is hard to do.So here’s an algebraic method.
If M(m1, m2) is the midpoint of two points A(x1, y1) and B(x2, y2),then m1 = (x1 + x2)/2 and m2 = (y1 + y2)/2.In other words, the x-coordinate of the midpointis the average of the x-coordinates of the two points,and the y-coordinate of the midpointis the average of the y-coordinates of the two points.
Let B have coordinates (x2, y2) in our problem.Then we have that 6 = (2 + x2)/2 and 8 = (3 + y2)/2.
Solving for the coordinates gives x2 = 10, y2 = 13
Try and find the common denominator which is 6 since 2×3 is 6 then once u get ur denominator u have to find the numerator which would be 4/6+3/6 And that would equal 7/6 and if you would u would keep it like that but if u would have to change it into a mixed fraction it would be 1 and 1/6
Hoped this helped
Answer:
x=1
y=-1/2
Step-by-step explanation:
x+2y=0....(1)
10y=-5.....(2)
From (2) we can find y.
y=-5/10
y=-1/2
Use that in (1)
x+2*(-1/2)=0
x-1=0
x=1
Answer:
hey it's you again. daniel
