We are given that a triangle ABC is a Right Angled Triangle. The side AB is hypotenuse, so the angle opposite to side AB which will be angle C is a Right Angle (measures 90 degrees)

We have the side length of all 3 sides. Based on this information, we can construct a triangle with given measures. The triangle is shown in the attached image.

We have to find the value of Sin(B). Sin of an angle is defined as:

$sin(\theta)=\frac{\text{Opposite Side}}{\text{Hypotenuse}}$

The side opposite to angle B is AC with a length of 3 and hypotenuse is side AB with length 5. So Sin of angle B would be:

$sin(B)=\frac{3}{5}$

8 0

3 years ago

Please help me i need someone to help!

Trava [24]

Answer:

so to do this we basicely just go through and substitute the anser in and see if it works.

60+10=70

60-10=50

50+20=70

50-20=30

RIGHT

so the answer is the second one

6 0

3 years ago