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2 years ago

WI MARK AS BRAINLIAST!! 20PTS!! PLS HELP ASAP!!!

Mathematics

2 answers:

earnstyle [38]2 years ago

6 0

Answer:

14. 118

15. 28

16. 152

Step-by-step explanation:

Firdavs [7]2 years ago

5 0

Answer:

m<CBE=118

m<ABF=28

m<CBA=152

Step-by-step explanation:

For Measure of CBE in order to determine the measure of the angle you must figure out what the supplementary angle is equal to. In this case it would be A and F. Subtract 62 from 90. Because all right angles are equal to 90.

Then you are left with 28. Add 28 to 90 and now you have your answer.

For angle ABF it is equal to 28. It is the same as the one I explained above

For CBA For CBA you already know that angle BCD is equal to 28. So all you have to do is subtract 28 from 180 because angles alike A to D are equal to 180.

Then you are left with 152 for ABF

Hope it helps

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Some one please help!

nasty-shy [4]

Answer:

The answers are 23, 9,200 and 26, 10,400

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

If a factory continuously dumps pollutants into a river at the rate of the quotient of the square root of t and 45 tons per day,

julsineya [31]

<h2>Hello!</h2>

The answer is:

The first option, the amount dumped after 5 days is 0.166 tons.

To solve the problem, we need to integrate the given expression and evaluate using the given time.

So, integrating we have:

$\int\limits^5_0 {\frac{\sqrt{t} }{45} } \, dt=\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \, dt\\\\\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \ dt=\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt\\\\\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt=(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)\\\\(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)=(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)$

$(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)=(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)\\\\(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)=(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)\\\\(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)=(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})\\\\(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})=\frac{2}{135}*11.18-0=0.1656=0.166$

Hence, we have that the amount dumped after 5 days is 0.166 tons.

Have a nice day!

5 0

3 years ago

What are the coordinates of B if (5,3) is 1/3 of the way from A to B

LenaWriter [7]

The coordinates would be 4,0?

7 0

2 years ago

Once a customer fills the car with gas at one station, that customer cannot then go fill the same car with gas at another statio

cluponka [151]

Answer:

yes :- P ( Ei ∩ Ej ) = 0

Step-by-step explanation:

These are mutually exclusive events

that is, a customer can only go to a gas station to fill his car with gas par time

P(E1) = 1/4

P(E2) = 1/4

P(E3) = 1/4

P(E4) = 1/4

summation of the four probabilities give 1

6 0

2 years ago

(11w^4 × 3z^9)(2w^7z^2)

mart [117]

Simplified:

11w^4(3)z^9(2w^7z^2)

=66w^11z^11

4 0

3 years ago

WI MARK AS BRAINLIAST!! 20PTS!! PLS HELP ASAP!!!​

WI MARK AS BRAINLIAST!! 20PTS!! PLS HELP ASAP!!!