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Licemer1 [7]
3 years ago
13

Question 7 (0.1 points)

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0

Answer:

c = 10

Step-by-step explanation:

5(2c + 5) – 5c = 2(3c+ 2) +11

Simplify...

5c+25=6c+15

Substract 6c from both sides...

5c+25-25=6c+15-25

5c=6c-10

-c=-10

Divide both sides by -1...

-c/-1 = -10/-1

c=10

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Pls help with my geometry!!
stealth61 [152]
Answer: 1: 45

Hope this helps!
6 0
3 years ago
What do u do on this question
Evgen [1.6K]
If Terrence is skating at a constant rate then the answer to b would be it is a function. On a You say how close he is to the motion detector in feet during the second he says. Since the seconds is on the first one 0 then he is 0 feet. Then 2, 4, 6, 8. Because every second he gets to feet colser. On c, the independent variable is how time, and the dependent variable is distance from motion detector. The independent variable is what you change and the dependent variable changes because of the independent variable. Hope this helped!
6 0
3 years ago
V(x)=x^2-25
Whitepunk [10]

Answer:

  -∞ < x < -5 ∪ -5 < x < -3/2 ∪ -3/2 < x < ∞

Step-by-step explanation:

The domain of any polynomial is "all real numbers." The domain of any rational function excludes any values of the variable that result in the denominator being 0. The function is "undefined" there.

__

  v(x)=\dfrac{x^2-25}{2x^2+13x+15}=\dfrac{(x+5)(x-5)}{(x+5)(2x+3)}\qquad x\notin \{-5,-\dfrac{3}{2}\}

The values x=-5 and x=-3/2 make the denominator of v(x) become 0, so those values are excluded from the domain of v(x). The function is "undefined" when its denominator is zero.

  -∞ < x < -5 ∪ -5 < x < -3/2 ∪ -3/2 < x < ∞

_____

<em>Additional comment</em>

The numerator and denominator factors (x+5) cancel each other, so there is no vertical asymptote at x=-5. Rather, the function has a "hole" there, where it is undefined. The limit as the function approaches x=-5 from either direction is v(x) = 10/7.

7 0
2 years ago
Answer:-<br><br><br> 5³<br> 4³<br><br> Thanks!
Lostsunrise [7]
These are exponents. To solve an exponent you need to multiply the base it self how many times its says in the power.

a² 

a = base
2 = power

5³ = 5 × 5 × 5 = 125
5³ = 125

4³ = 4 × 4 × 4 = 64
4³ = 64
3 0
3 years ago
Read 2 more answers
The distance a spring will stretch varies directly with how much weight is attached to the spring if a spring stretches 11 inche
Studentka2010 [4]

Answer:

the weight that attached to the spring is 9.5 inches

Step-by-step explanation:

The computation is shown below:

inches per pound is

= 11 inches ÷ 75 pounds

Now for 65 pounds, it would be

=  11 inches ÷ 75 pounds × 65 pounds

= 9.5 inches

Hence, the weight that attached to the spring is 9.5 inches

The same is relevant and considered

4 0
3 years ago
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