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3 years ago

The concentration of a drug in a patient's bloodstream t hours after injection is given by C =

Mathematics

1 answer:

Airida [17]3 years ago

8 0

i don't know

brainly ok?????

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-6000 divded 7680 please help me

SIZIF [17.4K]

It is -.78125 if you round it it’s 1

6 0

3 years ago

Read 2 more answers

Two middle school classes take a vote on the destination for a class trip. Class A has 25 students, 56% of whom voted to go to S

Kryger [21]

Answer:

The value of n is 15.

Step-by-step explanation:

The combined proportion is computed using the formula:

$P=\frac{n_{A}\cdot p_{A}+n_{B}\cdot p_{B}}{n_{A}+n_{B}}$

The information provided is as follows:

$n_{A}=25\\p_{A}=0.56\\n_{B}=n\\p_{B}=0.60\\P=0.575$

Compute the value of n as follows:

$P=\frac{n_{A}\cdot p_{A}+n_{B}\cdot p_{B}}{n_{A}+n_{B}}$

$0.575=\frac{25\times 0.56+n\times 0.60}{25+n}\\\\0.575(25+n)=14+0.60n\\\\14.375+0.575n=14+0.60n\\\\0.60n-0.575n=14.375-14\\\\0.025n=0.375\\\\n=15$

Thus, the value of n is 15.

6 0

2 years ago

The area of the red triangle is------ cm.

mr_godi [17]

Haudicjduyshsvdbcbis 2cn and yes it is

6 0

3 years ago

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If A^2=A, which matrix is matrix A

Ronch [10]

Consider all options:

$\left[\begin{array}{cc}5&5\\-4&-4\end{array}\right] \cdot \left[\begin{array}{cc}5&5\\-4&-4\end{array}\right] =\left[\begin{array}{cc}5\cdot 5+5\cdot (-4)&5\cdot 5+5\cdot (-4)\\-4\cdot 5+(-4)\cdot (-4)&-4\cdot 5+(-4)\cdot (-4)\end{array}\right]=$

$=\left[\begin{array}{cc}5&5\\-4&-4\end{array}\right].$

This option is true.

$\left[\begin{array}{cc}6&5\\5&6\end{array}\right] \cdot \left[\begin{array}{cc}6&5\\5&6\end{array}\right] =\left[\begin{array}{cc}6\cdot 6+5\cdot 5&6\cdot 5+5\cdot 6\\5\cdot 6+6\cdot 5&5\cdot 5+6\cdot 6\end{array}\right]=$

$=\left[\begin{array}{cc}61&60\\60&61\end{array}\right].$

This option is false.

$\left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right] \cdot \left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right] =\left[\begin{array}{cc}0.5\cdot 0.5+(-0.5)\cdot (-0.5)&0.5\cdot (-0.5)+(-0.5)\cdot 0.5\\-0.5\cdot 0.5+0.5\cdot (-0.5)&-0.5\cdot (-0.5)+0.5\cdot 0.5\end{array}\right]=$

$=\left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right].$

This option is true.

$\left[\begin{array}{cc}0.5&0.5\\-0.5&0.5\end{array}\right] \cdot \left[\begin{array}{cc}0.5&0.5\\-0.5&0.5\end{array}\right] =\left[\begin{array}{cc}0.5\cdot 0.5+0.5\cdot (-0.5)&0.5\cdot 0.5+0.5\cdot 0.5\\-0.5\cdot 0.5+0.5\cdot (-0.5)&-0.5\cdot 0.5+0.5\cdot 0.5\end{array}\right]=$

$=\left[\begin{array}{cc}0&0.5\\-0.5&0\end{array}\right].$

This option is false.

$\left[\begin{array}{cc}-6&-6\\5&5\end{array}\right] \cdot \left[\begin{array}{cc}-6&-6\\5&5\end{array}\right] =\left[\begin{array}{cc}-6\cdot (-6)+(-6)\cdot 5&-6\cdot (-6)+(-6)\cdot 5\\5\cdot (-6)+5\cdot 5&5\cdot (-6)+5\cdot 5\end{array}\right]=$