CL ≈ AE and HG≈ZR and ∠L≈∠E as both triangles are isosceles so CL=HL and AE=EZ
so HL≈AE≈ZR≈EZ so according to side angle side ΔCLH andΔ AZE both are congruent so side CH≈AZ
D is right because there is not tire
You cannot simplify 30/q anymore
Answer:
(f o g)(x)= 3x + 14
(g o f)(x) = 3x + 4
Step-by-step explanation:
(f o g)(x) = f(g(x)) = f(x + 5) = 3(x + 5) - 1 = 3x + 15 - 1 = 3x + 14
(g o f)(x) = g(f(x)) = g(3x - 1) = 3x - 1 + 5 = 3x + 4
60%
I pretty sure this is right
