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elena55 [62]
3 years ago
13

ANSWER SHEET

Mathematics
1 answer:
faust18 [17]3 years ago
5 0

Answer:

.

Step-by-step explanation:

You might be interested in
Solve (x + 3 < 5) U (x - 7 > 1).
ale4655 [162]

Answer:

{ x | x < 2 or x > 8}

Step-by-step explanation:

Given the expression

(x + 3 < 5) U (x - 7 > 1).

Solve x+3 < 5

Subtract 3 from both sides

x+3 - 3 < 5-3

x < 2

For x - 7 > 1

Add 7 to both sides

x-7+7 > 1 + 7

x > 8

Hence the union of both is { x | x < 2 or x > 8}

4 0
3 years ago
A center has a center at X(4, -3) and a point on the circle is W(8, 0). What is the location of Y on the diameter WY?
galben [10]

Answer: (0, -6)

Step-by-step explanation:

The center is the midpoint of the diameter, meaning that the coordinates of Y must be (0, -6).

4 0
2 years ago
My watch loses a quarter of a minute every hour . If i put it right at midday , what time will my watch show at 8pm that evening
Phantasy [73]

Answer:

7:58 PM

Step-by-step explanation:

8PM=20HRS

20:00                                                                      

-12:00

8HRS            8x60=480 MIN

           1/4x480=120 sec

120/6=2min

    8:00

-      :02

     7:58

4 0
4 years ago
Using all my points for this. Sorry for making somebody have to do this but I have to do some other homework on the side that I
givi [52]

Answer:

I am busy but all the questions from 1 to 6 just add the measure of 2 angles which are given and then subtract it from 180, you will get the measure of the remaining angle.

7.

8.: 180/3

9. x = 5

10. i dont know

i dont know = no time....

Step-by-step explanation:

8 0
3 years ago
Find the values of the trigonometric functions of t from the given information. cos(t) = − 8 17 , terminal point of t is in quad
____ [38]

Find the value of the trigonometric function of t form the given information

Cost=-8/17,terminal point of t is in quadrant 3rd in which cos<0, sin<0

Sint=-√(1-cos^2t)=-√(1-64/289)

=-√(225/289)=-15/17

Tant =sin/cos= -15/-8=15/8

Csc t=-17/15

Sect =-17/8

Cot=8/15


8 0
3 years ago
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