Reflection over the y-axis followed by a horizontal translation 1 unit left on the equation f(x)=x

Mathematics

1 answer:

aleksley [76]2 years ago

6 0

Answer:

f(x) = -x -4 or f(x) = (-x)-4

Step-by-step explanation:

Let the graph of g be a translation of 4 units down followed by a reflection in the y-axis of the graph of f(x)=x. Write a rule for g.

Transformations can be found using this general formula: f(x) = a(bx-h)+k

For this question, we want a translation down as well as a reflection.

The two values we need to use are for k, a vertical translation, and b, a reflection over the y-axis.

Since we are translating down 4 units, k = -4

Since we are reflecting across the y-axis, b = -1

So, f(x)=(-x)-4

f(x)= -x -4

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What is the sum of the arithmetic sequence 151, 137, 123,..if there are 26 terms?

ElenaW [278]

First term: a1 = 151
common difference: d = -14 (we decrease by 14 each time, eg, 151-14 = 137)

nth term of this arithmetic sequence is...
an = a1+d(n-1)
an = 151+(-14)(n-1)
an = 151-14n+14
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This will be used in the formula below

Sn = n*(a1+an)/2
Sn = n*(151+(-14n+165))/2
S26 = 26*(151+(-14*26+165))/2 ... replace every n with 26
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The final answer here is choice C) -624

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3 years ago

What is the volume of this cone?

olchik [2.2K]

Answer:

The volume of the cone is approximately 453.0 cm³

Step-by-step explanation:

The volume of a cone is one third that of a cylinder with the same height and radius. That gives us 1/3 πr²h, where r is radius and h is height.

However, we are not given the height of the cone, but the side length. We can work out the height using the Pythagorean theorem, as we have a right triangle with the height, base radius, and length. You may recall that the Pythagorean theorem states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of it's other two sides:

$a^2 = b^2 + c^2$

So we can find the height of the cone with that:

$10.8^2 = 7.4^2 + h^2\\h^2 = 10.8^2 - 7.4^2\\h^2 = 116.64 - 54.76\\h^2 = 61.88\\h = \sqrt{61.88}\\h \approx 7.9$

Now that we have the cone's height, we can solve for its volume:

$v = \frac{1}{3} \pi r^2 h\\v = \frac{1}{3} \pi \times 7.4^2 \times 7.9\\v = \frac{1}{3} \pi \times 54.76 \times 7.9\\v = \frac{1}{3} \pi \times 432.6\\v = \pi \times 144.2\\v \approx 453.0 cm^3$