Answer:
2a + 7
Step-by-step explanation:
-3a + 7 +5a
<em>subtract the negative 3 from the 5</em>
2a + 7
The mean to your problem is 87.5
The function you seek to minimize is
()=3‾√4(3)2+(13−4)2
f
(
x
)
=
3
4
(
x
3
)
2
+
(
13
−
x
4
)
2
Then
′()=3‾√18−13−8=(3‾√18+18)−138
f
′
(
x
)
=
3
x
18
−
13
−
x
8
=
(
3
18
+
1
8
)
x
−
13
8
Note that ″()>0
f
″
(
x
)
>
0
so that the critical point at ′()=0
f
′
(
x
)
=
0
will be a minimum. The critical point is at
=1179+43‾√≈7.345m
x
=
117
9
+
4
3
≈
7.345
m
So that the amount used for the square will be 13−
13
−
x
, or
13−=524+33‾√≈5.655m
Answer:
go left 2 and up 6
Step-by-step explanation:
(x,y)
(x,y) --> (-2,6)
0 = x 0 = y
0 - 2 = -2 = x
0 + 6 = 6 = y
(-2,6)
When making the X negative, you want to go left on the grid. When making Y positive, you want to go up on the grid.
Answer:
13
Step-by-step explanation:
x+y+z;
Let x=4, y=3, z=6
4+3+6
13
