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kondaur [170]
3 years ago
14

42,300 multiply by 10 can someone show the work

Mathematics
2 answers:
Assoli18 [71]3 years ago
3 0
       10
x42,300
-------------
          00
        000
     3,000
   20,000
400,000
-------------
423,000
Mrac [35]3 years ago
3 0
42.300 X 10 = 423,000.
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The leash will serve as the radius of the circle that Adrianne's dog will be running around on. 

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Solve for x in the equation x + 10 = 15.
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Suppose that Motorola uses the normal distribution to determine the probability of defects and the number of defects in a partic
Mekhanik [1.2K]

Answer:

\mathbf{P(X < 9.85 \ or \ X> 10.15) \approx 0.3171}     to four decimal places.

\mathbf{P(X < 9.85 \ or \ X> 10.15) =0.0027}  to four decimal places.

Step-by-step explanation:

a)

Assuming X to be the random variable which replace the amount of defectives and follows standard normal distribution whose mean  (μ) is 10 ounces and standard deviation (σ) is 0.15

The values of the random variable differ from mean  by ±  1 \such that the values are either greater than (10+ 0.15) or less than  (10-0.15)

= 10.15 or  9.85.

The  probability that the amount of defectives which are either greater than 10.15 or less than 9.85 can be calculated as follows:

P(X < 9.85 \ or \ X> 10.15) = 1-P ( \dfrac{9.85-10}{0.15}< \dfrac{X-10}{0.15}< \dfrac{10.15-10}{0.15})

P(X < 9.85 \ or \ X> 10.15) = 1- \phi (1) - \phi (-1)

Using the Excel Formula ( = NORMDIST (1) ) to calculate for the value of z =1 and -1 ;we have: 0.841345 and 0.158655 respectively

P(X < 9.85 \ or \ X> 10.15) = 1- (0.841345-0.158655)

P(X < 9.85 \ or \ X> 10.15) =0.31731

\mathbf{P(X < 9.85 \ or \ X> 10.15) \approx 0.3171}     to four decimal places.

b) Through process design improvements, the process standard deviation can be reduced to 0.05.

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P(X < 9.85 \ or \ X> 10.15) = 1-P ( \dfrac{9.85-10}{0.05}< \dfrac{X-10}{0.05}< \dfrac{10.15-10}{0.05})

P(X < 9.85 \ or \ X> 10.15) = 1- \phi (3) - \phi (-3)

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(c)  What is the advantage of reducing process variation, thereby causing process control limits to be at a greater number of standard deviations from the mean?

The main advantage of reducing the process variation is that the chance of getting the defecting item will be reduced as we can see from the reduction which takes place from a to b from above.

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Step-by-step explanation:

I think its 63 times because 50X60 will get you 3,000 and you already have 320 so 3,000+320 is 3,320 and when you add 50, 3 more times you get 3,470 so it would be 63 times

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