9514 1404 393
Answer:
A: x + y = 55; y - x = 25
B: 15 minutes running
C: no
Step-by-step explanation:
<h3>Part A:</h3>
The two equations relate to the total number of minutes, and to the difference specified in the problem statement.
x + y = 55 . . . . . . total time is 55 minutes
y = x + 25 . . . . . . dances 25 minutes longer
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<h3>Part B:</h3>
We can substitute for y in the first equation to find the value of x, the time spent running.
x + (x +25) = 55
2x = 30 . . . . subtract 25
x = 15 . . . . . . divide by 2
Jackie spends 15 minutes running each day.
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<h3>Part C:</h3>
The value of y from is found using the second equation:
y = x +25 = 15 +25 = 40
Jackie <u>will not spend 45 minutes dancing</u> if she meets the requirements on times.
Answer:
360 radical 2 or 509.11688
Step-by-step explanation:
simplify the radicals
12 =2 radical 3
calculate the products
10* 2 radical 3 * 6 radical 6
= 120 radical 18
again simplify
360 radical 2
Answer:
$4600
Step-by-step explanation:
$3000 to pay off the car + $1600 to repaint the kitchen = $4600 owed on the home equity line of credit
9514 1404 393
Answer:
Step-by-step explanation:
You have to realize that the absolute value function will change the sign of its argument only if that argument is negative.
108. |x -7| = x -7 . . . . . true for x-7≥0
x ≥ 7 . . . . makes the statement true
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1a. When m < 9, the value 6m is less than 54, so 6m-54 < 0. That means the absolute value function changes the sign of its argument:
54 -6m . . . . . simplified form for m < 9
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1b. |y -x| = y -x . . . when y > x, the argument of the absolute value is positive
Answer:
i do only 1 part
hope my answer is helpful to you
