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3 years ago

11

The area of a parallelogram is 273, and the lengths of its sides are 16 and 34. Determine, to the nearest tenth of a degree, the

measure of the obtuse angle of the parallelogram.

1 answer:

dangina [55]3 years ago

6 0

Answer: 30°

Step-by-step explanation:

solution is in the attachment

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Steve bought 47 pounds of peanuts that cost $0.89 per pound how much did he pay

erik [133]

Answer:

$41.83

Step-by-step explanation:

I believe its 0.89 multiplied by 47 that results to 41.83.

Please correct me if I'm wrong hehe.

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2 years ago

PLEASE HELP AND NO LINKS OR YOU WILL BE REPORTED. I need help with this, I chose the answer B but I’m afraid it’s wrong please h

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its

3 1/2

Step-by-step explanation:

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2 years ago

How can I do this ???

LuckyWell [14K]

Answer:

The triangle EFG can be constructed with the following specifications: $EF = 8\,cm$ , $FG = 7\,cm$ , $EG = 12\,cm$ , $E \approx 34.093^{\circ}$ , $F \approx 106.068^{\circ}$ , $G \approx 39.838^{\circ}$ .

Step-by-step explanation:

A triangle is formed by either knowing the lengths of its three sides or knowing two angles and the length of a side or knowing a angle and the lengths of two sides. By Geometry, we know that sum of internal angles in triangles equals 180°. In order to construct this triangle, we need to know the measures of angles E, F and G by means of the Law of Cosine:

Angle E

$E = \cos^{-1}\left[\frac{(7\,cm)^{2}-(12\,cm)^{2}-(8\,cm)^{2}}{-2\cdot (12\,cm)\cdot (8\,cm)} \right]$

$E \approx 34.093^{\circ}$

Angle F

$F = \cos^{-1}\left[\frac{(12\,cm)^{2} - (8\,cm)^{2} - (7\,cm)^{2}}{-2\cdot (8\,cm)\cdot (7\,cm)} \right]$

$F \approx 106.068^{\circ}$

Angle G

$G = \cos^{-1}\left[\frac{(8\,cm)^{2}-(12\,cm)^{2}-(7\,cm)^{2}}{-2\cdot (12\,cm)\cdot (7\,cm)} \right]$

$G \approx 39.838^{\circ}$

The triangle EFG can be constructed with the following specifications: $EF = 8\,cm$ , $FG = 7\,cm$ , $EG = 12\,cm$ , $E \approx 34.093^{\circ}$ , $F \approx 106.068^{\circ}$ , $G \approx 39.838^{\circ}$ .

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2 years ago

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kobusy [5.1K]

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Answer is B I’m sure

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