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Fed [463]
2 years ago
8

Which fraction is equal to 0.03 repating?

Mathematics
2 answers:
Soloha48 [4]2 years ago
6 0
<h2><em><u>correct answer: 1/33</u></em></h2>
Leni [432]2 years ago
4 0

Answer:

B

Step-by-step explanation:

A = 0.03, not repeating So it's not A

B = 0.03030303...  So It's correct

C = 0.0909090... So it's wrong

D = 0.33333333... It's not 0.03030303...

B is the correct answer. If this helped, please mark me as Brainliest. Thank you and have a nice day.

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One fourth divided by three eighths
balu736 [363]
Hello there
1\4 / 3\8 =8\12=2\3
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6 0
2 years ago
1. The graph of y = x2 is translated 4 units down and 3 units to the left. It is also stretched by a factor
slega [8]

Answer:

ok so first ur gonna do 4x3=12 then

Step-by-step explanation:

7 0
2 years ago
what is the y-intercept of the equation of the line that is perpendicular to the line y = 3/5x 10 and passes through the point (
bazaltina [42]
Perpendiculare means the slopes multiply to -1

y=3/5x+10
slope is 3/5
3/5 times what is -1
-5/3 is answer

slope of perpenduclar is-5/3 find y int
y=-5/3+b
point given is (15,-5)
x=15
y=-5

-5=-5/3(15)+b
-5=-25+b
add 25 to both sides
20=b

the yintercept is y=20 or the oint (0,20)
6 0
3 years ago
For an upcoming field trip to the science center, the school will allow students to select one extra activity. The school survey
Pani-rosa [81]

The total amount that would be spent on all the activities is  $1605.40.

<h3>What is the total amount?</h3>

The total amount that would be spent on movies = (14/25) x 1200 x 1.55  = $1041.60

The total amount that would be spent on planetarium tickets = (7/25) x 1200 x 1.05 =352.80

The total amount that would be spent on backstage passes = (4/25) x 1200 x 1.10 =211.20

Total amount = 211.20 + 352.80 +  $1041.60 = $1605.40

Please find attached the complete question. To learn more about addition, please check: brainly.com/question/349488

7 0
1 year ago
The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and
kykrilka [37]

Answer:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

<u>15                       7.50                                 7.50  </u>

<u>∑                                                               17.0281</u>

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

8 0
3 years ago
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