All categories

2 years ago

Which of the four triangles was formed by a translation of triangle EFG? A B C D

Mathematics

2 answers:

Serggg [28]2 years ago

7 0

It’s D I just answered the same question

Law Incorporation [45]2 years ago

3 0

$Question$

Which of the four triangles was formed by a translation of triangle EFG?

Answer:

Hi, There! ~Jay Here~ your Answer Is D But Let Me Help you Undertand It Better-

translation is a transformation that occurs when a figure is moved from one location to another location without changing its size, shape or orientation.

Meaning It Is Not Moving The Shape Any angle or Else

Step-by-step explanation:

D: Triangle is a translation 6 units to the left translation is where something is moved horisontally or vertically.

Hope this helps!

You might be interested in

If an object is dropped from a height of 55 feet, the function d = -16^2 + 55 gives the height of the object after t seconds. Gr

motikmotik

Answer:

Approximately 1.9 seconds (correct to nearest tenth)

Step-by-step explanation:

Looks like the function is d = -16t^2 + 55 ( you left out the t)

The answer is the value of t when d = 0 so we have the equation:-

0 = -16t^2 + 55

16t^2 = 55

t^2 = 55/16

t = sqrt (55/16)

= 1.85 seconds

4 0

2 years ago

Read 2 more answers

Penny and Sheldon are assembling hair clips. Penny can assemble a hair clip in 6 minutes and Sheldon can assemble a hair clip in

creativ13 [48]

The answer would be 18 minutes

8 0

2 years ago

Answer the question pls

masha68 [24]

Answer:

f=54

Step-by-step explanation:

ma is m times a 3x18= 54

6 0

2 years ago

Read 2 more answers

In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p

skelet666 [1.2K]

Answer:

$\mathbf{P(X=5) =0.0888}$

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

$\mathtt{P(X=x) =(^{n}_{x} ) \ \pi^x \ (1-\pi)^{n-x}}$

$\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} ) \ \pi^x \ (1-\pi)^{n-x}}$

where;

n = 8 and π = 0.36

For x = 5

The probability $\mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} ) \ 0.36^5 \ (1-0.36)^{8-5}}$

$\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} ) \ 0.36^5 \ (0.64)^{3}}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =({8 \times 7 } ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =0.0887645}$

$\mathbf{P(X=5) =0.0888}$ to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5) $\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})$

${P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times (0.36)^0 \times (1-0.36)^8 \ ) + \dfrac{8!}{1!(7!)} \times (0.36)^1 \times (1-0.36)^7 \ +$ $\dfrac{8!}{2!(6!)} \times (0.36)^2 \times (1-0.36)^6 \ + \dfrac{8!}{3!(5!)} \times (0.36)^3 \times (1-0.36)^5 + \dfrac{8!}{4!(4!)} \times (0.36)^4 \times (1-0.36)^4 \ + \dfrac{8!}{5!(3!)} \times (0.36)^5 \times (1-0.36)^3 \ )$