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3 years ago

Which of the following is the surface area of the right cylinder below radius 7 height 2

Mathematics

2 answers:

Dimas [21]3 years ago

5 0

7^2 times 2 which is 49.2 and it is 98

juin [17]3 years ago

3 0

$\bf \textit{surface area of a cylinder}\\\\ SA=2\pi r(h+r)~~ \begin{cases} r=radius\\ h=height\\ -----\\ r=7\\ h=2 \end{cases}\implies SA=2\pi (7)(2+7) \\\\\\ SA=14\pi (9)\implies SA=126\pi$

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What is the value of this expression when a = 2 and b = -3 ? a^3 - b^3 / 5

saveliy_v [14]

Answer:

13 2/5

Step-by-step explanation:

a = 2 and b = -3

so the question asks whats.... a^3 - b^3/5

First we plug in the values of a and b

(2)^3 - (-3)^3 /5

Now we solve the ones in paranthesis first

(2)^3 = 8 because 2×2×2 and

-(-3)^3 forget about the - outside the parenthesis so

(-3)^3 = (-27) because (-3)×(-3)×(-3)

now we put it back together

8 -(-27)/5

the two minus become plus so

8 + 27/5

Now we solve it like fractions

8 and 27/5

simplify

13 and 2/5

Hope that helps!

5 0

2 years ago

Solve -7x^2+x+9=-6x quadratic formula

myrzilka [38]

Answer:

$-7x^2+x+9=-6x$

$-7x^2+x+9+6x=-6x+6x$

$-7x^2+7x+9=0$

$quadratic\: formula$

$x_{1,\:2}=\frac{-7\pm \sqrt{7^2-4\left(-7\right)\cdot \:9}}{2\left(-7\right)}$

$\sqrt{-7^{2} -4(-7)\times9} =\sqrt{301}$

$x_{1,\:2}=\frac{-7\pm \sqrt{301}}{2\left(-7\right)}$

$\frac{-7+\sqrt{301}}{2\left(-7\right)}$

$=\frac{-7+\sqrt{301}}{-2\cdot \:7}$

$=\frac{-7+\sqrt{301}}{-14}$

$\frac{-7-\sqrt{301}}{2\left(-7\right)}$

$=\frac{-7-\sqrt{301}}{-2\cdot \:7}$

$=\frac{-7-\sqrt{301}}{-14}$

$answer=\frac{7+\sqrt{301}}{14}$

$OAmalOHopeO$

7 0

3 years ago

What is the 72nd term of arithmetic sequence-27,-11,5

otez555 [7]

Answer:

1109

Step-by-step explanation:

you can subtract the terms to see the difference between them

-11-(-27)=16

The sequence is increasing by 16

you can plug that 16 in the formula for d

a_n=a_1+(n-1)d

a_n=a_1+(n-1)16

n represents the term you want to find in this case the 72nd

a sub 1 is the first term of the sequence in this case -27

a_72=-27+(72-1)16

a_72=-27+(71)16

a_72=-27+1136

a_72=1109

7 0

2 years ago

Read 2 more answers

The two triangles below are similar. What value of Q and B would make this true

Alenkinab [10]

Answer:

∠B = ∠Q = 26°

Step-by-step explanation:

The angles B and Q should be same, therefore:

Q = 4x + 2 and B = 15x - 64

The equation below as per above, solving for x:

4x + 2 = 15x - 64
15x - 4x = 64 +2
11x = 66
x = 6

Then the angle measures:

4*6 + 2 = 26°

6 0

3 years ago

I the equation 3x^2+6x=12, the value of c is?

ozzi

Answer:

c = -12

Step-by-step explanation:

Quadratic Standard Form: ax² + bx + c

Step 1: Write equation

3x² + 6x = 12

Step 2: Subtract 12 on both sides

3x² + 6x - 12 = 0

Here, we have the standard form of the quadratic. We see that our c = -12

4 0

3 years ago