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2 years ago

Which of the following is the surface area of the right cylinder below radius 7 height 2

Mathematics

2 answers:

Dimas [21]2 years ago

5 0

7^2 times 2 which is 49.2 and it is 98

juin [17]2 years ago

3 0

$\bf \textit{surface area of a cylinder}\\\\ SA=2\pi r(h+r)~~ \begin{cases} r=radius\\ h=height\\ -----\\ r=7\\ h=2 \end{cases}\implies SA=2\pi (7)(2+7) \\\\\\ SA=14\pi (9)\implies SA=126\pi$

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Will give brainliest, <br> (404/4)x(2x2) to the power of 2.

Ganezh [65]

Answer:

163216

Step-by-step explanation:

If it's the sign of multiplication

404/4=101

2*2=4*101=404^2=163216

or,

If it's x

(404/4)x(2x2)

(101)x(2x2)

101x (4x)^2

1616x^2

2611456

I am not sure if it's right

7 0

2 years ago

What is the distance between (8, -3) and (4, – 7)?

Dahasolnce [82]

Answer:

Step-by-step explanation:

using

$\sqrt{(x2 - x1) + (y2 - y1)}$

$\sqrt{(8 - 3) + (4 - ( - 7)}$

$\sqrt{5 + 11}$

$\sqrt{16}$

$= 4$

7 0

2 years ago

Read 2 more answers

Can someone help me on this mess...

serg [7]

Answer:

sas

Step-by-step explanation:

5 0

2 years ago

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A local bakery has a daily operating cost of $1800 plus a cost of $10 per cake

Delicious77 [7]

Answer:

B. 15c > 1,800 + 10c

Step-by-step explanation:

Profit=Total revenue - total cost

Profit is achieved:

when total revenue is greater than total cost

TR>TC

When total cost is less than total revenue

TC<TR

From the question

Total cost=1800+10c

Total revenue=15c

Profit=TR>TC or TC<TR

15c>1800+10c

1800+10c<15c

Option B. 15c > 1,800 + 10c satisfies the condition that Profit=TR>TC

4 0

3 years ago

Read 2 more answers

A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f

mestny [16]

Answer:

The value is $W= 2640 \ ft \cdot lb$

Step-by-step explanation:

From the question we are told that

The weight of the bucket is $F = 5 lb$

The depth of the well is $x_1 = 60 \ ft$

The weight of the water is $W_w = 42 lb$

The rate at which the bucket with water is pulled is $v = 1.5 \ ft/s$

The rate of the leak is $r = 0.15 lb/s$

Generally the workdone is mathematically represented as

$W = \int\limits^{x_1}_{x_o} {G(x)} \, dx$ ]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

$G(x) = F + (W_w- Ix)$

Here I is the rate of water loss in lb/ft mathematically represented as

$I = \frac{r}{v}$

=> $I = \frac{0.15 }{1.5 }$

=> $I = 0.1$

$G(x) = 5 + (42- 0.1x)$

=> $G(x) = 47- 0.1x)$

$W = \int\limits^{60}_{0} {47- 0.1x} \, dx$ ]

=> $W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.$

=> $W= [47(60) - 0.05(60)^2]$

=> $W= 2640 \ ft \cdot lb$

7 0

2 years ago