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motikmotik
3 years ago
5

A car travel 252 mile on 9 gallons of gasoline. How many gallons of gas will it need to go 140 miles

Mathematics
1 answer:
spin [16.1K]3 years ago
8 0

Answer:

5

Step-by-step explanation:

It runs 28 mpg. Divide 140 by 28 to get 5

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What is the rate of change of the function?
olga_2 [115]

Answer:

3

Step-by-step explanation:

the rate of change of the function, or the slope is 3 because to get to one point from the other point in the line, you would have to go up 3 and over 1 (3/1) or just 3.

Hope this helps

5 0
3 years ago
Read 2 more answers
Use the distributive property two different ways to find the product of 127 and 32
cricket20 [7]
127 = 100 +27
32 = 30 +2
so 127 x 32 = (100 + 27) x (30+2) = (100x30) + (100x2) + (27x30) +(27x2)
= 3000+200+810+54 = 4064

second way:

127 = 100 + 27
127 x 32 = (100+27) x 32 = (100x 32) + ( 27x32) = 3200 + 864 = 4064
5 0
3 years ago
How many fire extinguishers must be carried onboard motorized boats, with installed fuel tanks, that are between 26 and 40 feet
vlabodo [156]

<span>The number of fire-extinguisher that are required to be carried onboard motorized boats depends on the size of the boat. The main purpose of fire extinguishers is for the protection of the motor engine. Thus, For a 26 and 40 feet in length, at-least two B-I extinguishers or one B-II are required to carry.</span>

8 0
3 years ago
A random sample of 250 students at a university finds that these students take a mean of 15.3 credit hours per quarter with a st
SpyIntel [72]

Answer:  15.3\pm0.198

OR

(15.102, 15.498)

Step-by-step explanation:

The formula to find the confidence interval(\mu) is given by :-

\overline{x}\pm z_{\alpha/2, df}\dfrac{s}{\sqrt{n}}

, where n is the sample size

s = sample standard deviation.

\overline{x}= Sample mean

z_{\alpha/2} = Two tailed z-value for significance level of \alpha .

Given : Confidence level = 95% = 0.95

Significance level = \alpha=1-0.95=0.05

s= 1.6

\overline{x}=15.3

sample size : n= 250 , which is extremely large ( than n=30) .

So we assume sample standard deviation is the population standard deviation.

thus , \sigma=1.6

By standard normal  distribution table ,

Two tailed z-value for Significance level of 0.05 :

z_{\alpha/2}=z_{0.025}=1.96

Then, the 95% confidence interval for the mean credit hours taken by a student each quarter :-

15.3\pm (1.96)\dfrac{1.6}{\sqrt{250}}\\\\ =15.3\pm 0.19833\\\\=\approx15.3\pm0.198\\\\=(15.3-0.198,\ 15.3+0.198)=(15.102,\ 15.498)

Hence, the mean credit hours taken by a student each quarter using a 95% confidence interval. =(15.102, 15.498)

5 0
3 years ago
4 times the sum of x and 0.5 *
Fynjy0 [20]
4(x+0.5) is the answer if your trying to simplify it
4 0
3 years ago
Read 2 more answers
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