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3 years ago

HELP PLEASSEEE!!!

Mathematics

1 answer:

Oksana_A [137]3 years ago

7 0

Answer:B

Step-by-step explanation:

human blood needs to saty harm in cold areas

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2x + y = 3

Leto [7]

It should be B 3y=5 hope I'm right.

3 0

3 years ago

a skydiver jumps out of an airplane after 0.8 second she has fallen 100 feet after 3.1 seconds she has fallen 500 feet Emtiaz sa

Dennis_Churaev [7]

The answer may be no, because half of 500 is 250, and half of 3 is 1.5. If this is true, than the skydiver should fall 250 ft in 1.5 seconds.

7 0

3 years ago

Read 2 more answers

HELP ASAP LIMITED TIME

natita [175]

Answer:

Step-by-step explanation:

not explaining but its B trust me

8 0

4 years ago

What is the graph of the function = f of x equals negative x squared minus 9 x minus 20 all over x plus 4 ?

alisha [4.7K]

Answer:

See below

Step-by-step explanation:

Lets do the long division:-

- x - 5

-------------------

x + 4 ( -x^2 - 9x - 20

-x^2 - 4x Subtract:-

------------

-5x - 20

The quotent is -x - 5 with no remainder so the graph will be a straight line with negative slope of -1, and y-intercept at (0, -5).

4 0

3 years ago

Rewrite sin 15 degree in terms of a 75 degree angle and in terms of the reciprocal of a trigonometric function.

NeX [460]

$\bf csc(\theta)=\cfrac{1}{sin(\theta)}
\\\\\\
sin({{ \alpha}} - {{ \beta}})=sin({{ \alpha}})cos({{ \beta}})- cos({{ \alpha}})sin({{ \beta}})\\\\
-------------------------------\\\\
sin(15^o)\implies sin(45^o-30^o)
\\\\\\
sin(45^o)cos(30^o)-cos(45^o)sin(30^o)$

$\bf \cfrac{\sqrt{2}}{2}\cdot \cfrac{\sqrt{3}}{2}-\cfrac{\sqrt{2}}{2}\cdot \cfrac{1}{2}\implies \cfrac{\sqrt{6}}{4}-\cfrac{\sqrt{2}}{4}\implies \cfrac{\sqrt{6}-\sqrt{2}}{4}\\\\
-------------------------------\\\\
csc(15^o)=\cfrac{1}{sin(15^o)}\implies csc(15^o)=\cfrac{1}{\frac{\sqrt{6}-\sqrt{2}}{4}}
\\\\\\
csc(15^o)=\cfrac{4}{\sqrt{6}-\sqrt{2}}$

and now, we can rationalize the denominator by using its conjugate and difference of squares.

$\bf \cfrac{4}{\sqrt{6}-\sqrt{2}}\cdot \cfrac{\sqrt{6}+\sqrt{2}}{\sqrt{6}+\sqrt{2}}\implies \cfrac{4(\sqrt{6}+\sqrt{2})}{(\sqrt{6}-\sqrt{2})(\sqrt{6}+\sqrt{2})}
\\\\\\
\cfrac{4(\sqrt{6}+\sqrt{2})}{(\sqrt{6})^2-(\sqrt{2})^2}\implies \cfrac{4(\sqrt{6}+\sqrt{2})}{6-2}\implies \boxed{\sqrt{6}+\sqrt{2}}$

6 0

3 years ago