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3 years ago

HELP PLEASE!!!! THANK YOU

Mathematics

2 answers:

lozanna [386]3 years ago

7 0

Answer:

I think it's right skewed.

Step-by-step explanation:

Lisa [10]3 years ago

6 0

Answer: Left skewed

Step-by-step explanation:

Most of the data such as the q1,median,q3,minuium and maximum are all on the left side of the box plot.

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Mrs. Jackson gives the table below to her students.

krek1111 [17]

M= 20 because the rate of change is -3.

5 0

3 years ago

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Use cubic regression to find a function that fits the following points.

8090 [49]

Answer:

y = 2x³ + x² - 4x + 6

Step-by-step explanation:

General formula:

y = ax³ + bx² + cx + d

If you replace point (0, 6) in the general formula, you get:

6 = a(0)³ + b(0)² + c(0) + d

6 = d

If you replace points (-1, 9), (1, 5) and (2, 18) in the general formula, you get the following system of equations:

9 = a(-1)³ + b(-1)² + c(-1) + 6

9 = -a + b - c + 6 (eq. 1)

5 = a(1)³ + b(1)² + c(1) + 6

5 = a + b + c + 6 (eq. 2)

18 = a(2)³ + b(2)² + c(2) + d

18 = 8a + 4b + 2c + 6 (eq. 3)

Adding equation 1 to equation 2:

14 = 2b + 12

(14 - 12)/2 = b

b = 1

Multiplying equation 1 by 2:

18 = -2a + 2b - 2c + 12 (eq. 4)

Adding equation 4 to equation 3, and replacing with b value:

36 = 6a + 6b + 18

36 = 6a + 6 + 18

(36 - 6 - 18)/6 = a

a = 2

Replacing a and b values in equation 1:

9 = -2 + 1 - c + 6

c = -2 + 1 + 6 - 9

c = -4

8 0

3 years ago

Read 2 more answers

Question and possible answers in image

IRISSAK [1]

Im not sure use a caculator with it

8 0

3 years ago

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-9(-3k+6w) use w=8 and k=2

Ludmilka [50]

W=8
k=2

-9(-3k+6w)
-9(-3(2)+6(8)
-9(-6+48)
-9(42)
-378

The answer is -378

7 0

3 years ago

What is the solution set of the equation using the quadratic formula?

oee [108]

(1)

we are given

$x^2+6x+10=0$

we can use quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

now, we can compare and find a , b and c

we get

$a=1,b=6,c=10$

now, we can plug these values into quadratic formula

$x=\frac{-6\pm \sqrt{6^2-4(1)(10)}}{2(1)}$

$x=\frac{-6+\sqrt{6^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}$

we can simplify it

$x=-3+i$

$x=\frac{-6-\sqrt{6^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}$

$x=-3-i$

so, we will get solution

{−3+i, −3−i}.........Answer

(2)

we are given equation as

$x^2-8x+14=0$

Since, Jamal solve this equation by completing square

so, firstly we will move constant term on right side

so, subtract both sides by 14

$x^2-8x+14-14=0-14$

$x^2-8x=-14$

we can write

$-8x=-2\times 4\times x$

so, we will add both sides by 4^2

$x^2-8x+4^2=-14+4^2$

we get

$x^2-8x+16=-14+16$ ..............Answer

4 0

3 years ago