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2 years ago

Help please I really need help :)

Mathematics

1 answer:

Firdavs [7]2 years ago

6 0

Answer:

Solution given:

For 1st

x²=71

For x=± $\sqrt{71}$

and

For 2nd

x³=71

For x=± $\sqrt[3]{71}$

So answer is:

In first row

Solution to x²=71

In second row

Solution to x³=71

In third row

neither

In forth row

Solution to x³=71

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The population of a small town is 40,740. It's population falls by 8% per year. How many years later will the population be 14,5

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Answer:

0.9101523758 ≈ 1 year

Step-by-step explanation:

The population of a small town is 40,740.

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Read 2 more answers

in 2012, the population of a city was 63,000. by 2017, the population was reduced to approximately 54,100. identify any equation

Akimi4 [234]

Answer:

$f(x) = 63000(0.97)^x$

Step-by-step explanation:

Given

$f(0) = 63000$ ---x = 0, in 2012

$f(5) = 54100$ -- x = 5, in 2017

Required

Select all possible equations

Because there is a reduction in the population, as time increases; the rate must be less than 1.

An exponential function is represented as:

$f(x) = ab^x$

Where

$b = rate$

rate > 1 in options (a) and (b) i.e. 1.03

This implies that (a) and (b) cannot be true

For option (c), we have:

$f(x) = 63000(0.97)^x$

Set x = 0

$f(0) = 63000(0.97)^0 = 63000*1=63000\\$

Set x = 5

$f(5) = 63000(0.97)^5 = 63000*0.8587=54098.1 \approx 54100$

This is true because the calculated values of f(0) and f(5) correspond to the given values

For option (d), we have:

$f(x) = 52477(0.97)^x$

Set x = 0

$f(0) = 52477(0.97)^0 - 52477* 1 = 52477$

This is false because the calculated value of f(0) does not correspond to the given value

For option (e), we have:

$f(x) = 63000(0.97)^\frac{1}{5x}$

Set x = 0

$f(0) = 63000(0.97)^\frac{1}{5*0} = 63000(0.97)^\frac{1}{0} =$ undefined

This is false because the f(x) is not undefined at x = 0

For option (f), we have:

$f(x) = 52477(0.97)^{5x$

Set x = 0

$f(0) = 52477(0.97)^{5*0} = 52477(0.97)^0 =52477*1= 52477$

This is false because the calculated value of f(0) does not correspond to the given value

From the computations above, only (c) $f(x) = 63000(0.97)^x$ is true

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3 years ago