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3 years ago

8

Find the distance traveled by a car moving at an average speed of 40 miles per hour 3 hours.

1 answer:

Grace [21]3 years ago

6 0

Answer: 120 miles traveled

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An object is launched at 28 meters per second (m/s) from a 336-meter tall platform. The equation for the object's height s at ti

kondaur [170]

Answer:343 m

Step-by-step explanation:

Given

launch velocity of object is $u=28\ m/s$

height of Platform $h=336\ m$

height of object is given by

$s(t)=-7t^2+14t+336$

For maximum height velocity of object is zero

i.e. $\frac{ds}{dt}=0$

$\frac{ds}{dt}=-14t+14+0=0$

$t=\frac{14}{14}=1\ s$

Therefore after 1 sec object achieves maximum height

$s(1)=-7(1)+14(1)+336$

$s(1)=343\ m$

3 0

4 years ago

Which of the following shows why rectangle WXYZ is congruent to rectangle W'X'Y'Z'?

blsea [12.9K]

If you rotated the box 90º, the orrientation would not be the same, so it is not D or B.

After rotating 180º, the box will be in the 1st quadrant. If it moved along the x-axis, it wouldnt be there anymore, and the after-picture shows it in the first quadrant still, so the only answer it can be is C.

3 0

3 years ago

Please help!! it could go towards my gcses and i’m clueless

eimsori [14]

Answer:X=34

Step-by-step explanation:

ok it is easy

7 0

3 years ago

This is a polygon with three sides.

poizon [28]

Answer: A three-sided polygon is a triangle.

There are several different types of triangle (see diagram), including: Equilateral – all the sides are equal lengths, and all the internal angles are 60°. Isosceles – has two equal sides, with the third one a different length.

Step-by-step explanation:

6 0

3 years ago

The mean June midday temperature in Desertville is 36°C and the standard deviation is 3°C.Assuming this data is normally distrib

AleksandrR [38]

Answer:

The value is $E(X) = 4 \ days$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 36^oC$

The standard deviation $\sigma = 3^oC$

Generally the probability that in June , the midday temperature is between

39°C and 42°C is mathematically represented as

$P(39 < X < 42) = P(\frac{39 - 36}{3} < \frac{X - \mu }{\sigma} < (\frac{42 - 36}{3} )$

$\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )$

$P(39 < X < 42) = P(1 < Z$

=> $P(39 < X < 42) = P(Z < 2) - P( Z$

From the z table the area under the normal curve to the left corresponding to 1 and 2 is

P(Z < 2) = 0.97725

and

P(Z < 1) = 0.84134

$P(39 < X < 42) = 0.97725 - 0.84134$

=> $P(39 < X < 42) = 0.13591$

Generally number of days in June would you expect the midday temperature to be between 39°C and 42°C

$E(X) = n * P(39 < X 42 )$

Here n is the number of days in June which is n = 30

$E(X) = 30 * 0.13591$

=> $E(X) = 4 \ days$

8 0

3 years ago