All categories

3 years ago

Find the distance traveled by a car moving at an average speed of 40 miles per hour 3 hours.

Mathematics

1 answer:

Grace [21]3 years ago

6 0

Answer: 120 miles traveled

You might be interested in

Factor the polynomial F(x) =x^3-x^2-4x+4 completely.

Norma-Jean [14]

Answer:

Step-by-step explanation:

PART 1:

Possible roots by noticing the coefficient of first term:

x = 1, -1

PART 2:

1 | 1 -1 -4 4

1 0 -4 0

The remainder is zero, hence one factor is (x-1)

PART 3:

$x^3-x^2-4x+4=(x^2-4)(x-1)\\\\x^3-x^2-4x+4=(x+2)(x-2)(x-1)$

PART 4:

$f(x)=(x+2)(x-2)(x-1)\\\\=(x^2-4)(x-1)\\\\=x^3-4x-x^2+4\\\\=x^3-x^2-4x+4$

6 0

3 years ago

Find the area of the shaded polygons:

tigry1 [53]

Answer:

Step-by-step explanation:

Purple: This makes two trapezoids. A=(a+b)/2 times h

1st = (4+1)/2 x 1 = 2.5

2nd = (4+1)/2 x 3 = 5/2 x 3 = 2.5x3=7.5

Total = 2.5+7.5=10

Green: if you draw a line down the center, you can divide these into two more manageable triangles. A=1/2bh

1st = 1/2x2x2 = 2

2nd = 1/2x2x2 = 2

Total = 2+2=4

6 0

3 years ago

I need some help, can't figure out this last question.

Damm [24]

He now has 36 percent

5 0

2 years ago

Atmospheric pressure decreases by about 11.8% for every 1000 meters you climb. The pressure at sea level is 1013 millibars (a un

erica [24]

At sea level, the pressure is 1013, that's when the altitude is at 0, sea level, let's see

$\bf \textit{Periodic Exponential Decay}\\\\
A=I(1 - r)^{\frac{t}{p}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &1013\\
I=\textit{initial amount}\\
r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\
t=\textit{meters climbed}\to &0\\
p=period\to &1000
\end{cases}
\\\\\\
1013=I(1-0.118)^{\frac{0}{1000}}\implies 1013=I\cdot 1\implies 1013=I$

so, the inital amount is 1013, when t = 0,

$\bf \textit{Periodic Exponential Decay}\\\\
A=I(1- r)^{\frac{t}{p}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &1013\\
r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\
t=\textit{meters climbed}\to &t\\
p=period\to &1000
\end{cases}
\\\\\\
A=1013(1-0.118)^{\frac{t}{1000}}\implies A=1013(0.882)^{\frac{t}{1000}}$

now, to check the atmospheric pressure at 4000, simply set t = 4000, to get A.

7 0

3 years ago

Thrice a number subtracted from 10?

Mkey [24]

Answer:

10-3x

Step-by-step explanation:

let the number=x

thrice the number becomes 3x

7 0

2 years ago