So the possible ways of throwing a sum of 10 is 4&6, 5&5, 6&4. All possible ways of throwing a pair of dice equal 36, so divide 3 by 36. Then, divide this number by 9 to get the possibility of it being at least 9 times, because the last throw doesn't affect it.
Answer:
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Step-by-step explanation:
Answer: 76 m^2
Step-by-step explanation:
Answer:
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Answer:
Probability that Ryan is both certified and has never had an accident is undefined
Step-by-step explanation:
Given;
Probability that Garrick is certified = P(G) = {25}
Probability that Molly has not had an accident = P(M) = {71.87}
Probability that Ryan is both certified and has never had an accident = P(R) = {?}
Probability of Ryan being certified was not defined,
Probability that Ryan has not had an accident was not also defined
Therefore, Probability that Ryan is both certified and has never had an accident = P(R) = is undefined, since Ryan is not within the given set.
