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2 years ago

Which expression is equivalent to 5 (3+4)? A) 15 + 20 B) 15 + 4 © 8 + 9 D) 15 + 9

Mathematics

2 answers:

insens350 [35]2 years ago

7 0

Answer:

15 + 20

Step-by-step explanation:

if it is correct then please mark as a brainlist

Eva8 [605]2 years ago

4 0

Answer:

A. 15+ 20

Step-by-step explanation:

5(3+4)

5(7)

=35

A. 15+20 = 35

35=35

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3 years ago

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3 years ago

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3 years ago

What additional information could be used to prove ABC MQR using SAS?

Igoryamba

Answer:

To prove that ΔABC ≅ ΔMQR using SAS, we show that two sides with the intersection angle are congruent.

From the diagram, it is shown that CA is congruent to RM.

From the first option, given that m∠A = 64° and AB = MQ = 31 cm, then we have CA = RM, AB = MQ, and CAB = RMQ (i.e. m∠A = m∠M = 64°).

This shows that the first option is correct.

From the second option, given that CB = MQ = 29 cm, then we have CA = RM, CB = MQ, but ACB is not congruent to RMQ.

Thus the second option in not correct.

From the third option, m∠Q = 56° and CB ≅ RQ, then we have CA = RM, CB = RQ, ACB = 60°, but we do not know the value of MRQ.

Thus the third option is not correct.

From the fourth option, m∠R = 60° and AB ≅ MQ, then we have CA = RM, AB = MQ, RMQ = 64°, but we do not know the value of CAB.

Thus the fourth option is not correct.

From the fifth option, AB = QR = 31 cm, then we have CA = RM, AB = QR, but we do not know the value of CAB or MRQ.

Thus, the fifth option is not correct.

Therefore, the additional information that could be used to prove ΔABC ≅ ΔMQR using SAS is m∠A = 64° and AB = MQ = 31 cm

6 0

3 years ago

Wendy took a trip from one city to another, a distance of 500 mi. She traveled part of the way by bus, which arrived at the trai

Fynjy0 [20]

Answer- Wendy spent 3 hours on the train

Solution-

The distance between the cities= 500 mi.

She traveled part of the way by bus, and other part by train.

The bus averaged 40 mph, and the train averaged 120 mph.

The entire trip took 6.5 hours.

let d = distance traveled by train

the total distance was given as 500 mi ,

therefore, distance traveled by bus = (500-d) mi

time = distance/speed

⇒ train traveling time + bus traveling time = 6.5 hrs

⇒ $\frac{d}{120} +\frac{500-d}{40} = 6.5$

⇒ d + 3(500-d) = 120(6.5)

⇒ d + 1500 - 3d = 780

⇒ 2d = 720

⇒ d = 360 mi

so d = 360 mi by train

⇒ 360/120 = 3 hrs on the train

8 0

3 years ago