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cupoosta [38]
3 years ago
8

Which domain restrictions apply to the rational expression?

Mathematics
1 answer:
dimulka [17.4K]3 years ago
5 0

1) it must be fulfilled that the denominator is different from zero, then for this expression

x^2 -9  ⇒ x^2-3^2 = (x-3)(x+3)⇒ (x-3)(x+3) = 0 ⇒ x = 3 o x = -3 , the dominium is all numbers reals except 3 and -3  

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Franco is at the state fair with some friends. He is deciding between buying a jumbo pack of 50 ride tickets for $45 or a medium
jasenka [17]

Answer:

The jumbo pack is a better deal

Step-by-step explanation:

The better deal of two is the one that offers a lower cost per ride. Considering the two deals, the cost per unit ride for;

a jumbo pack of 50 ride tickets for $45 = $45/50

= $0.90 per ride

a medium pack of 30 ride tickets for $28.50

= $28.50/30

= $0.95

From the computations above, the medium pack (at $0.95) is more costly than the jumbo pack (at $0.90). Hence the jumbo pack is a better deal for Franco.

5 0
3 years ago
what are the coordinate points of A’,B’, and C’ after they were translated right 4 units and up 1 unit??
Alisiya [41]

Answer:

A' = ( -2 , 6 )

B' = ( 7 , 3 )

C' = ( 4 , 0 )

Step-by-step explanation:

Itz askin that if each point is to be shifted 4 units right & 1 unit up then what's the co-ordinates of the new points .

The initial point of A = ( -6 , 5 )

When we shift A for 4 units right , the its abscissa = -6 + 4 = -2 (∵ Right side is considered as positive. So that's why it's +4 )

When we shift A for 1 unit up , its ordinate = 5 + 1 = 6 (∵ Upper side is considered as positive. So that's why it's +1 )

Hence , co-ordinates of A' = ( -2 , 6 )

The initial point of B = ( 3 , 2 )

When we shift A for 4 units right , the its abscissa = 3 + 4 =  7

When we shift A for 1 unit up , its ordinate = 2 + 1 = 3

Hence , co-ordinates of B' = ( 7 , 3 )

The initial point of C = ( 0 , -1 )

When we shift A for 4 units right , the its abscissa = 0 + 4 =  4

When we shift A for 1 unit up , its ordinate = -1 + 1 = 0

Hence , co-ordinates of C' = ( 4 , 0 )

5 0
3 years ago
Follow the directions to solve the system of equations by elimination. 8x + 7y = 39 4x – 14y = –68 Multiply the first equation t
Helga [31]

Answer:

x=½

y=5

Step-by-step explanation:

(8x+7y=39)2

16x+14y=78

<u>4</u><u>x</u><u>-</u><u>1</u><u>4</u><u>y</u><u>=</u><u>-</u><u>6</u><u>8</u> add the two equations

20x=10.

divide both sides by 20

x=½

8x+7y=39

4+7y=39

7y=39-4

7y=35

y=5

7 0
4 years ago
Read 2 more answers
A recipe uses 5 cups of milk to make 10 servings. If the same amount of milk is used for each serving, how many servings can be
kodGreya [7K]
16 servings

because there are 4 cups in a quart, and two quarts is 8 cups.. if 5 cups of milk makes 10 servings there is half a cup in each serving.. so 8/.5 is 16
4 0
3 years ago
Read 2 more answers
4. Point V is somewhere on UW. If UV - 2x - 13, VW--18+ 2x, and UW = 17, then find the length of UV.
Slav-nsk [51]

The length of UV is 11.

Solution:

UV = 2x - 13

VW = -18 + 2x

UW = 17

UV + VW = UW

2x - 13 - 18 + 2x = 17

4x - 31 = 17

Add 31 on both sides.

4x - 31 + 31 = 17 + 31

4x = 48

Divide by 4 on both sides.

$\frac{4x}{4} =\frac{48}{4}

x = 12

UV = 2x - 13

     = 2(12) - 13

     = 24 - 13

UV = 11

The length of UV is 11.

4 0
3 years ago
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