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iris [78.8K]
3 years ago
5

Quick brain for first and 5 stars What steps should be taken to calculate the volume of the right triangular prism? Select three

options.
A triangular prism. The triangular base has a base of 8 meters and height of 14 meters. The height of the prism is 7 meters.
Use the formula A = one-half b h to find the area of the base.
Use the formula A = b h to find the area of the base.
The area of the base, A, is One-half (7) (8) = 28 meters squared.
The area of the base, A, is One-half (8) (14) = 56 meters squared.
The volume of the prism, V is (56) (7) = 392 meters cubed.
Mathematics
2 answers:
Ierofanga [76]3 years ago
8 0

Answer:

- Use the formula A = one-half b h to find the area of the base.

- The area of the base, A, is One-half (8) (14) = 56 meters squared.

- The volume of the prism, V is (56) (7) = 392 meters cubed

Step-by-step explanation:

To find the volume of right triangular prism, the following steps should be followed:

The formula bfor calculating the volume = Base Area × Height.

Step 1:

- Use the formula A = one-half b h to find the area of the base.

This formula of a triangle bus used because the base of a triangular prism is triangular in nature.

b is the base of the triangle

h is the height of the triangle

Step 2:

Given base if triangle = 8m

Height of triangle = 14m

We substitute this values into the formula of the base area to have the second step:

Base area = 1/2(8)(14) = 56m²

- The area of the base, A, is One-half (8) (14) = 56 meters squared.

Step 3:

Then we calculate the volume if the prism where height of the prism is 8m

volume of the prism = 56 × 7

= 392m³.

This gives us the final step

- The volume of the prism, V is (56) (7) = 392 meters cubed

Bumek [7]3 years ago
7 0

Answer:

a,d,e

Step-by-step explanation:

:3

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This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

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b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

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The first (k less or equal to 5) is already calculated.

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P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}

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The sum of the probabilities is

P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981

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