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vlada-n [284]
2 years ago
10

Differentiate in respect to x

Mathematics
1 answer:
mixer [17]2 years ago
3 0

Answer:

e^{2x}(2x^3+3x^2)

Step-by-step explanation:

Use the Product Rule  (uv)' = uv' + u'v

\frac{d}{dx}(x^3 e^{2x})=x^3\frac{d}{dx}(e^{2x})+\frac{d}{dx}(x^3)e^{2x}\\=x^3(2e^{2x})+3x^2e^{2x}\\=e^{2x}(2x^3+3x^2)

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Answer:

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Step-by-step explanation:

The equation setup I used for this was as follows: $16 x (112/36)

Using PEMDAS, you'd start with the division part, 112/36. Although, I did this a bit differently, and being a bit further in school, I don't know if you go through this where you're at.

Start by factoring 112 into 4(28). This leaves you with 4(28)/36.

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