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vlada-n [284]
3 years ago
10

Differentiate in respect to x

Mathematics
1 answer:
mixer [17]3 years ago
3 0

Answer:

e^{2x}(2x^3+3x^2)

Step-by-step explanation:

Use the Product Rule  (uv)' = uv' + u'v

\frac{d}{dx}(x^3 e^{2x})=x^3\frac{d}{dx}(e^{2x})+\frac{d}{dx}(x^3)e^{2x}\\=x^3(2e^{2x})+3x^2e^{2x}\\=e^{2x}(2x^3+3x^2)

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