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WINSTONCH [101]
3 years ago
10

100 PLZ HELP NO LINK AND IF YOU GUESS YOU GET REPORTED

Mathematics
1 answer:
Vika [28.1K]3 years ago
6 0
The answer should be (-1/3,3/4) if I did the math correct
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The volume of a prism is 48 cubic centimeters. If the length is 2 centimeters and the width is 4 centimeters. What is the height
Pie

Answer:

6

Step-by-step explanation:

volume is (lwh) since youre trying to find the height just multiply the 2 and 4 together to get 8. Then divide 8 by 48 to get your height.

4 0
3 years ago
65 POINTS PLEASE HELP
miskamm [114]

Answer:

        1  

= -----------

   6(x + 7)

Step-by-step explanation:

3x - 21      x^2 - 49

----------- ÷ -------------

18x - 18        x - 1

3x - 21          x - 1

----------- ×  -------------

18x - 18       x^2 - 49

Factor the top left:

3x - 21  = 3(x - 7)

Factor the bottom left:

18x - 18 = 18(x - 1)

Factor the new bottom right:

x^2 - 49 = (x + 7)(x - 7)

Multiply and simplify the faction:

3(x - 7)            x - 1

----------- ×  -----------------

18(x - 1)       (x + 7)(x - 7)

        1  

= -------------

   6(x + 7)

6 0
3 years ago
Read 2 more answers
What is the area of this face?
raketka [301]
200 inches bc 10x10 +10x10 is 200
8 0
2 years ago
Read 2 more answers
Can you help me solve this because i am stuck on this problem. Thx
sineoko [7]
So 2.5 os to 50, aka 2.5:50
divide each side by 2.5 to get the answer.
if you dont have a calculator, divide each side by 5 to get .5:10, multiply by 2 to get 1:20
7 0
3 years ago
Read 2 more answers
he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s
sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

P(X

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) =[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

NORMSDIST(6.366)-NORMSDIST(-1.47)

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0
2 years ago
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