QUESTION 1

sergejj [24]

Answer:

Jet engines move the airplane forward with a great force that is produced by a tremendous thrust and causes the plane to fly very fast. All jet engines, which are also called gas turbines, work on the same principle. The engine sucks air in at the front with a fan. ... Spinning the turbine causes the compressor to spin.

Explanation:

yw

8 0

3 years ago

A plate (A-C) is connected to steelflat bars by pinsat A and B. Member A-E consists of two 6mm by 25mm parallel flat bars. At C,

juin [17]

Answer:

stress_ac = 5.333 MPa

shear stress_c = 1.763 MPa

Explanation:

Given:

- The missing figure is in the attachment.

- The dimensions of member AC = ( 6 x 25 ) mm x 2

- The diameter of the pin d = 19 mm

- Load at point A is P = 2 kN

Find:

- Find the axial stress in AE and the shear stress in pin C.

Solution:

- The stress in member AE can be calculated using component of force P along the member AE as follows:

stress_ac = P*cos(Q) / A_ae

Where, Angle Q: A_E_B and A_ac: cross sectional area of member AE.

cos(Q) = 4 / 5 ..... From figure ( trigonometry )

A_ae = 0.006*0.025*2 = 3*10^-4 m^2

Hence,

stress_ae = 2*(4/5) / 3*10^-4

stress_ae = 5.333 MPa

- The force at pin C can be evaluated by taking moments about C equal zero:

(M)_c = P*6 - F_eb*3

0 = P*6 - F_eb*3

F_eb = 0.5*P

- Sum of horizontal forces for member AC is zero:

P - F_eb - F_c = 0

F_c = 0.5*P

- The shear stress of double shear bolt is given by an expression:

shear stress = shear force / 2*A_pin

Where, The area of the pin C is:

A_pin = pi*d^2 / 4

A_pin = pi*0.019^2 / 4 = 2.8353*10^-4 m^2

Hence,

shear stress = 0.5*P / 2*A_pin

shear stress = 0.5*2 / 2*2.8353*10^-4

shear stress = 1.763 MPa

7 0

3 years ago

What should be a concern as a weldment becomes larger as more parts are added?

Ludmilka [50]

Shhdudhgfhycvbbgvfhfkyfvjhv

7 0

3 years ago

Steam enters a turbine operating at steady state at 2 MPa, 323 °C with a velocity of 65 m/s. Saturated vapor exits at 0.1 MPa an

Lera25 [3.4K]

Answer:

$\dot Q_{out} = 13369.104\,kW$

Explanation:

The turbine is modelled after the First Law of Thermodynamics:

$-\dot Q_{out} - \dot W_{out} + \dot H_{in} - \dot H_{out} + \dot K_{in} - \dot K_{out} + \dot U_{in} - \dot U_{out} = 0$

The rate of heat transfer between the turbine and its surroundings is:

$\dot Q_{out} = \dot H_{in}-\dot H_{out} + \dot K_{in} - \dot K_{out} - \dot W_{out} + \dot U_{in} - \dot U_{out}$

The specific enthalpies at inlet and outlet are, respectively:

$h_{in} = 3076.41\,\frac{kJ}{kg}$

$h_{out} = 2675.0\,\frac{kJ}{kg}$

The required output is:

$\dot Q_{out} = \left(8\,\frac{kg}{s} \right)\cdot \left\{3076.41\,\frac{kJ}{kg}-2675.0\,\frac{kJ}{kg}+\frac{1}{2}\cdot \left[\left(65\,\frac{m}{s} \right)^{2}-\left(42\,\frac{m}{s} \right)^{2}\right] + \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m) \right\} - 8000\,kW$ $\dot Q_{out} = 13369.104\,kW$

4 0

3 years ago

You are provided the following information about a municipal wastewater treatment plant. This plant uses the traditional activat

3241004551 [841]

Answer:

Explanation:

Attached is the solution

5 0

3 years ago