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denpristay [2]
3 years ago
13

When considering free energy change, biochemists usually define a standard state, the biochemical standard state, which is modif

ied from the chemical standard state to fit biochemical applications. Determine which of the phrases describe the biochemical standard state, the chemical standard state, or both.
Engineering
1 answer:
Softa [21]3 years ago
3 0

Answer:

Maximum work under this condition (∆G) = Maximum work under Standard Condition (∆G°) + Activities defining this condition

Explanation:

In this equation, the term DGo provides us with a value for the maximal work we could obtain from the reaction starting with all reactants and products in their standard states, and going to equilibrium. The term DG' provides us with a value for the maximal work we could obtain under the conditions defined by the activities in the logarithmic term. The logarithmic term can be seen as modifying the value under standard conditions to account for the actual conditions. In describing the work available in metabolic processes, we are concerned with the actual conditions in the reaction medium (whether that is a test-tube, or the cell cytoplasm); the important term is therefore DG'. If we measure the actual activities (in practice, we make do with concentrations), and look up a value for DGo in a reference book, we can calculate DG' from the above equation.

Values for DGo provide a useful indication through which we can compare the relative work potential from different processes, because they refer to a standard set of conditions.

Therefore both phrases describe the Biochemical and Chemical Standard State

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A mass of 1.9 kg of air at 120 kPa and 24°C is contained in a gas-tight, frictionless piston–cylinder device. The air is now com
emmainna [20.7K]

Answer:

W=-260.66 kJ (negative answer means, that the work was done on the gas)

Explanation:

1) Convert temperature from C to K- T=24+273=297K- all temperature in the gas problems should be used in Kelvins;

2) We need to analyse type of the process- it is given, that the temperature is constant, so it is an Isothermal process, which means, that the equation of the process is: pV=const (constant);

3) Work, done on the system, should be calculated using the following equation: W=\int\limits^{Vb}_{Va} {p} \, dV

4) To calculate initical and final volumes (Va and Vb), we can use the following equation: pV=mRT, so V=mRT/p. Note, that the pressure is changing, thus we can calculate volumes for the both cases- initial and final, using initial (120kPa) and final (600kPa) pressures, in addition, we can find equation for the pressure, as function of the volume, which we need to use for the integration in step 3: p=mRT/V;

5) Now we can calculate the integral, given in the step 3: W=mRT ln(\frac{Vb}{Va}). As we have pressure as a known values, we can re-write the equation, using pressures: W=mRT ln(\frac{pa}{pb})=1.9*0.287*279*ln(\frac{120}{160})=-260.66 kJ

Note, that natural logarithm (ln) yields negative answer, which supports the question, that the work was done on the gas, not by the gas.

6 0
3 years ago
8. Air at 25C, 100 kPa and air at 50C, 200 kPa at 1 to 1 volume ratio are mixed inside an adiabatic compressor to 55C, 500 kPa a
quester [9]

Answer:

Workdone, w = 68.935 kJ

Explanation:

m1h1 + m2h2 + Q = m3h3 - Wc

Final mass of mixture,

m3 = m1 + m2 = 5kg

p1V1 = m1R1T1

p2V2 = m2R2T2

Since they are at 1:1,

V1 = V2 and R1 = R2

Comparing equations,

p1/p2 = (m1/m2) x (T1/T2)

m1/m2 = (100/200) x ((50 + 273)/(25+273))

m1/m2 = 0.542

m1 = 0.542m2

m3 = m1 + m2

5 = m2 + 0.542m2

m2 = 3.243kg

m1 = 1.757 kg

Workdone is given as,

Wc = m3h3 - m1h1 - m2h2

h = Cp x T, since air is an ideal gas

Cp = 1.005kJ/kGK

Wc = (5 x 1.005 x (55+273)) - (1.757 x 1.005 x 298) -(3.243 x 1.005 x 323)

Wc = 68.935 kJ

8 0
4 years ago
1. A screw driver with a 1.5 inch diameter handle is used to install a 1/4-20 UNC screw. Determine the circumference where the e
marishachu [46]

Explanation:

1. Circumference of the handle (where the effort is applied) is pi times diameter.

C = πd

C = 1.5π inches

C ≈ 4.71 inches

2. Mechanical advantage is the ratio of distance in over distance out.

MA = din / dout

MA = 1.5 / 0.25

MA = 6

3. Mechanical advantage is the ratio of force out over force in.

MA = Fout / Fin

6 = Fout / 10 lb

Fout = 60 lb

8 0
3 years ago
Dampers dampers springs are used inside some valve spring to
harkovskaia [24]
The correct answer is A. Retain. Valve Stem seals
3 0
3 years ago
From the article "Time Travel Is A Fun Science Fiction Story But Could It Be Real?", Albert Einstein's Theory of Relativity is d
zhannawk [14.2K]

Answer:

Option A

Explanation:

As per the article "Time Travel Is A Fun Science Fiction Story But Could It Be Real?" the gravitational field is a representation of curving space and time. As the gravity becomes strong, the space-time get more curved and hence the time gets slower.

Hence, option A is correct

8 0
3 years ago
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