Question

Suppose that the weight of an newborn fawn is Uniformly distributed between 1.8 and 3.3 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible.
The mean of this distribution is _____
The standard deviation is _____
The probability that fawn will weigh exactly 2.1 kg is P(x = 2.1) = _____
The probability that a newborn fawn will be weigh between 2.1 and 2.7 is P(2.1 < x < 2.7) = _____
The probability that a newborn fawn will be weigh more than 2.1 is P(x > 2.1) = _____
P(x > 2.5 | x < 3.1) = _____
Find the 66th percentile. _____

Answer 1

Answer:

That A Newborn Fawn Is Randomly Selected. Round All Answers To Two Decimal Places A. The Mean Of This Distribution Is B. The Standard Deviation Is C. The Probability That The Fawn Will Weigh More Than 2.8 Kg. D. Suppose That It Is Known That The Fawn Weighs Less

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Suppose that the weight of an newborn fawn is uniformly distributed between 2 and 4 kg. Suppose that a newborn fawn is randomly selected. Round all answers to two decimal places

A. The mean of this distribution is

B. The standard deviation is

C. The probability that the fawn will weigh more than 2.8 kg.

D. Suppose that it is known that the fawn weighs less than 3.5 kg. Find the probability that the fawn weights more than 3 kg.

E. Find the 90th percentile for the weight of fawns.

Explanation:

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