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TiliK225 [7]
3 years ago
14

What are the zeros of (3x-1)(2x-5)

Mathematics
1 answer:
otez555 [7]3 years ago
4 0

Answer:

x = -1 / 3

Step-by-step explanation:

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DaniilM [7]

Answer:

Huh

Step-by-step explanation:

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<em><u>T</u></em><em><u>H</u></em><em><u>A</u></em><em><u>N</u></em><em><u>G</u></em><em><u>I</u></em><em><u>N</u></em><em><u>A</u></em><em><u> </u></em><em><u>M</u></em><em><u>O</u></em><em><u> </u></em><em><u>T</u></em><em><u>A</u></em><em><u>N</u></em><em><u>O</u></em><em><u>N</u></em><em><u>G</u></em><em><u> </u></em><em><u>M</u></em><em><u>O</u></em><em><u> </u></em><em><u>S</u></em><em><u>A</u></em><em><u> </u></em><em><u>P</u></em><em><u>A</u></em><em><u>G</u></em><em><u>O</u></em><em><u>N</u></em><em><u>G</u></em><em><u> </u></em><em><u>V</u></em><em><u>O</u></em><em><u>V</u></em><em><u>O</u></em><em><u> </u></em><em><u>M</u></em><em><u>O</u></em><em><u> </u></em><em><u>V</u></em><em><u>O</u></em><em><u>V</u></em><em><u>O</u></em><em><u> </u></em><em><u>T</u></em><em><u>A</u></em><em><u>L</u></em><em><u>A</u></em><em><u>G</u></em><em><u>A</u></em><em><u> </u></em><em><u>1</u></em><em><u>V</u></em><em><u>1</u></em><em><u> </u></em><em><u>M</u></em><em><u>L</u></em>

3 0
2 years ago
Can someone help me?
Pie

Answer:

x = 12 efg = 132

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
How to show these 2 problems are inverses
nataly862011 [7]
\bf \begin{cases}&#10;f(x)=\sqrt[3]{7x-2}\\\\&#10;g(x)=\cfrac{x^3+2}{7}&#10;\end{cases}\\\\&#10;-----------------------------\\\\&#10;now&#10;\\\\&#10;f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2}&#10;\\\\\\&#10;\sqrt[3]{x^3}\implies x\\\\&#10;-----------------------------\\\\&#10;or&#10;\\\\&#10;g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7}&#10;\\\\\\&#10;\cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x

thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other
8 0
3 years ago
A.) 170<br> B.) 300<br> C.)280<br> D.)155<br> Please help me
pav-90 [236]

Answer:

Step-by-step explanation:

The formula for this is

∠G = 1/2(arcEH - arcHF)

We have angle G (5x - 10) and we have arcEH (195) so we have to solve for x to find the measure of arcEHF so we can add arcEH + arcHF = arcEHF

Filling in the formula with what we have:

5x-10=\frac{1}{2}(195-(8x+17))

which simplifies down a bit to

5x-10=\frac{1}{2}(195-8x-17) which simplifies down a bit more to

5x-10=\frac{1}{2}(178-8x) Multiply both sides by 2 to get rid of the fraction and get:

2(5x - 10) = 178 - 8x which of course simplifies to

10x - 20 = 178 - 8x. Now add 8x to both sides and at the same time add 20 to both sides to get:

18x = 198 so

x = 11. Now we can find the measure of arcHF:

arcHF is 8x + 17, so arcHF is 8(11) + 17 which is 105°.

arcEH + arcHF = arcEHF so

195 + 105 = arcEHF so

arcEHF = 300°

6 0
3 years ago
Which of the following graphs would represent the solution set for y&lt;6x-2
OverLord2011 [107]
Where is the graph but in this case the y intercept would be -2 and you slope is 6 so go up 6 and to the right one and go down six and to the left one and thats what the graph should look like
5 0
3 years ago
Read 2 more answers
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