Answer:
5.15
Step-by-step explanation:
<u>Answer-</u>
The equation that describes the pattern is,

<u>Solution-</u>
P = Number of minutes Rodney spends practicing playing the piano
G = Number of minutes Rodney spends practicing playing the guitar
Taking P on x axis and G on y axis, the points are,

Taking first two points i.e
, the line equation will be,






Putting the other two points i.e
in the equation, they also satisfy the equation. That means they are also on the same line
.
From the result, it is evident that P and G are linearly related.
Answer:
This tells us that:
![A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%267%5C%5C5%26-8%5C%5C3%26-9%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
So we are saying we have scalars, c and d, such that:
.
So we want to find a way to express this as:
Ax=b where x is the scalar vector,
.
So we can write this as:
![\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%267%5C%5C5%26-8%5C%5C3%26-9%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dc%5C%5Cd%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-16%5C%5C3%5C%5C-15%5Cend%7Barray%7D%5Cright%5D)
If this is asking for the nearest hundred thousand, and not ten thousand, than you would round up to 100,000. 91,284 is close to 100,000.
Answer:
1. (2x^2+x-1)
Step-by-step explanation:
expanding (2x^2-1)^2. multiplying (x-2) (1-2x)
= 4x^2-4x+1. = x-2x^2-2+4x
= -2x^2+5x-2
(4x^2-4x+1-2x^2+5x-2)
=2x^2+x-1