Answer:
1.300
Step-by-step explanation:
so you round your tenths which is 2 then use the 5 to make it 1.300
hope this help :)
Answer:
Step-by-step explanation:
Hello!
The objective is to determine if there is any difference between using iPads vs textbooks in teaching algebra.
Two middle school classes were selected, to eliminate any other source of variation, the same teacher taught both classes, and the materials were provided by the same author and publisher. After a month 10 students of each class were randomly selected and tested, their test scores were recorded:
X₁: test scores of students that used iPads to study.
n₁= 10
X[bar]₁= 86.8
S₁= 8.97
X₂: test scores of students that used regular textbooks to study.
n₂= 10
X[bar]₂= 79.5
S₂= 10.8
a.
H₀: μ₁=μ₂
H₁: μ₁≠μ₂
α:0.05
Assuming that both variables are normally distributed and the population variances are equal, the statistic to use is a Student t for two independent samples with pooled sample variance:
![t_{H_0}= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }](https://tex.z-dn.net/?f=t_%7BH_0%7D%3D%20%5Cfrac%7B%28X%5Bbar%5D_1-X%5Bbar%5D_2%29-%28Mu_1-Mu_2%29%7D%7BSa%2A%5Csqrt%7B%5Cfrac%7B1%7D%7Bn_1%7D%20%2B%5Cfrac%7B1%7D%7Bn_2%7D%20%7D%20%7D)
![Sa^2= \frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2}](https://tex.z-dn.net/?f=Sa%5E2%3D%20%5Cfrac%7B%28n_1-1%29S%5E2_1%2B%28n_2-1%29S%5E2_2%7D%7Bn_1%2Bn_2-2%7D)
![Sa^2= \frac{9*80.4609+9*116.64}{10+10-2} = 98.55](https://tex.z-dn.net/?f=Sa%5E2%3D%20%5Cfrac%7B9%2A80.4609%2B9%2A116.64%7D%7B10%2B10-2%7D%20%3D%2098.55)
Sa= 9.93
![t_{H_0}= \frac{86.8-79.5}{9.93\sqrt{\frac{1}{10} +\frac{1}{10} } } = 1.64](https://tex.z-dn.net/?f=t_%7BH_0%7D%3D%20%5Cfrac%7B86.8-79.5%7D%7B9.93%5Csqrt%7B%5Cfrac%7B1%7D%7B10%7D%20%2B%5Cfrac%7B1%7D%7B10%7D%20%7D%20%7D%20%3D%201.64)
p-value: 0.118364
The p-value is greater than the significance level so the decision is to not reject the null hypothesis. This means that there is no significant evidence between the scores of the two groups.
b.
95% CI
(X[bar]-X[bar])±
*![Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }](https://tex.z-dn.net/?f=Sa%5Csqrt%7B%5Cfrac%7B1%7D%7Bn_1%7D%20%2B%5Cfrac%7B1%7D%7Bn_2%7D%20%7D)
![t_{n_1+n_2-2;1-\alpha /2}= t_{18;1.975}= 2.101](https://tex.z-dn.net/?f=t_%7Bn_1%2Bn_2-2%3B1-%5Calpha%20%2F2%7D%3D%20t_%7B18%3B1.975%7D%3D%202.101)
(86.8-79.5)±2.101*(9.93
)
[-2.03; 16.63]
With a 95% confidence level, you'd expect that the interval [-2.03; 16.63] would contain the difference between the mean scores of the two classes.
c.
Considering that the null hypothesis wasn't rejected and that at the same level the confidence interval includes the zero, we can affirm that the format of the teaching materials, digital or regular textbooks, has no significant effect on the scores of the students.
I hope it helps!
Answer:
the supplementary angle to 313 would be 49.
Step-by-step explanation:
the supplement of an angle is when tow angles add up to equal 180 degrees. therefore, if you subtract 131 from 180, you would get the answer of 49 degrees.
Answer:
<em>a. $42,572 at 2%, </em>
<em>b. $35,559 at 5% </em>
<em>c. $29,702 at 8% </em>
Step-by-step explanation:
The formula used for FV calculation for Continuous Compounding is as under:
![FV = PV e^{i * t}](https://tex.z-dn.net/?f=FV%20%3D%20PV%20e%5E%7Bi%20%2A%20t%7D)
Where,
FV = Future Value = $8000 each year (At the end of 6 years = $8000 x 6 = $48,000)
PV = Present Value
e = Mathematical Constant = 2.713
i = Interest Rate
t= time in years
a) For 2%:
![FV = PV e^{i * t}\\48000 = PV e^{0.02 * 6}\\48000 = 1.1275 (PV)\\PV = 42,572](https://tex.z-dn.net/?f=FV%20%3D%20PV%20e%5E%7Bi%20%2A%20t%7D%5C%5C48000%20%3D%20PV%20e%5E%7B0.02%20%2A%206%7D%5C%5C48000%20%3D%201.1275%20%28PV%29%5C%5CPV%20%3D%2042%2C572)
b) For 5%:;
![FV = PV e^{i * t}\\48000 = PV e^{0.05 * 6}\\48000 = 1.35 (PV)\\PV = 35,559\\](https://tex.z-dn.net/?f=FV%20%3D%20PV%20e%5E%7Bi%20%2A%20t%7D%5C%5C48000%20%3D%20PV%20e%5E%7B0.05%20%2A%206%7D%5C%5C48000%20%3D%201.35%20%28PV%29%5C%5CPV%20%3D%2035%2C559%5C%5C)
c) For 8%:
![FV = PV e^{i * t}\\48000 = PV e^{0.08 * 6}\\48000 = 1.616 (PV)\\PV = 29,702](https://tex.z-dn.net/?f=FV%20%3D%20PV%20e%5E%7Bi%20%2A%20t%7D%5C%5C48000%20%3D%20PV%20e%5E%7B0.08%20%2A%206%7D%5C%5C48000%20%3D%201.616%20%28PV%29%5C%5CPV%20%3D%2029%2C702)
Note: <em>Investing $42,572 at 2%, $35,559 at 5% and $29,702 at 8% today will get $48,000 at the end of 6 years. </em>