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scoray [572]
3 years ago
6

Is the following statement true or false? Every line segment has a length.

Mathematics
1 answer:
nata0808 [166]3 years ago
8 0

Answer:

True!

Step-by-step explanation:

A line segment is a line drawn between two points . Therefore, it has definite length .

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After that day, the high schooler never had an all nighter for the rest of high school. (College is a different story)

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8 0
3 years ago
Use the theorem on inverse functions to prove that f and g are inverse functions of each other. f(x) = 3x − 2 g(x) = x + 23
nignag [31]

Answer:

I need these points more than you do

Step-by-step explanation:

What do we do

6 0
3 years ago
Please help me with this. I thought the answer was 9 but I was wrong.
Lilit [14]

I think your answer is 28

3 0
3 years ago
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Use f(x) = 1/2 x and f -1(x) = 2x to solve the problems. f(2) = 1 f−1(1) = 2 f−1(f(2)) = 2 f−1(−2) = f(−4) = f(f−1(−2)) =
vampirchik [111]

Answer:

In this problem, we are given the following functions:

f(x)=\frac{1}{2}x

and its inverse function:

f^{-1}(x)=2x

First of all, we want to calculate f(2). This can be obtained by substituting

x = 2

into f(x). Doing so, we find:

f(2)=\frac{1}{2}\cdot 2 = 1

Then we want to calculate f^{-1}(1). We can do it by substituting

x = 1

into f^{-1}(x). Doing so,

f^{-1}(1)=2\cdot 1 = 2

Then we want to calculate f^{-1}(f(2)), which can be found by calculating f(2) and then using it as input for f^{-1}(x). We know that

f(2) = 1

Therefore,

f^{-1}(f(2))=f^{-1}(1)=2

Then we want to calculate f^{-1}(-2), which can be calculated by plugging

x = -2

into f^{-1}(x). Doing so,

f^{-1}(-2)=2\cdot (-2)=-4

Then we want to calculate f(-4); by substituting

x = 4

into f(x), we find

f(-4)=\frac{1}{2}\cdot (-4)=-2

Finally, we want to find f(f^{-1}(-2))

We know already that

f^{-1}(-2)=-4

So we have:

f(f^{-1}(-2))=f(-4)=-2

7 0
3 years ago
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No files or links please!<br> graph y= -4/3 x+2 using the slope and y-intercept
ValentinkaMS [17]

Answer:

heres a graph

Step-by-step explanation:

4 0
2 years ago
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